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A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s⁻2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s⁻2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s⁻2)
- a)0.2
- b)0.4
- c)0.6
- d)0.8
Correct answer is option 'D'. Can you explain this answer?
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A body of mass 10 kg lies on a rough horizontal surface. When a horizo...
/s^2. The coefficient of kinetic friction between the body and the surface is:
The force acting on the body can be calculated using Newton's second law:
F = ma
Where m is the mass of the body and a is its acceleration. Substituting the given values, we get:
F = 10 kg x 5 m/s^2 = 50 N
The force of friction acting on the body can be calculated using the formula:
f = μkN
Where μk is the coefficient of kinetic friction and N is the normal force acting on the body. The normal force is equal to the weight of the body, which is given by:
N = mg
Where g is the acceleration due to gravity. Substituting the given values, we get:
N = 10 kg x 9.8 m/s^2 = 98 N
Substituting the values of N and f in the formula for friction, we get:
50 N = μk x 98 N
Solving for μk, we get:
μk = 50 N / 98 N = 0.51
Therefore, the coefficient of kinetic friction between the body and the surface is 0.51.
The force acting on the body can be calculated using Newton's second law:
F = ma
Where m is the mass of the body and a is its acceleration. Substituting the given values, we get:
F = 10 kg x 5 m/s^2 = 50 N
The force of friction acting on the body can be calculated using the formula:
f = μkN
Where μk is the coefficient of kinetic friction and N is the normal force acting on the body. The normal force is equal to the weight of the body, which is given by:
N = mg
Where g is the acceleration due to gravity. Substituting the given values, we get:
N = 10 kg x 9.8 m/s^2 = 98 N
Substituting the values of N and f in the formula for friction, we get:
50 N = μk x 98 N
Solving for μk, we get:
μk = 50 N / 98 N = 0.51
Therefore, the coefficient of kinetic friction between the body and the surface is 0.51.
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A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s2)a)0.2b)0.4c)0.6d)0.8Correct answer is option 'D'. Can you explain this answer?
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A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s2)a)0.2b)0.4c)0.6d)0.8Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s2)a)0.2b)0.4c)0.6d)0.8Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s2)a)0.2b)0.4c)0.6d)0.8Correct answer is option 'D'. Can you explain this answer?.
A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s2)a)0.2b)0.4c)0.6d)0.8Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s2)a)0.2b)0.4c)0.6d)0.8Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5 m−s2. And when the horizontal force is doubled, it gets an acceleration of 18 m−s2. The coefficient of friction between the body and the horizontal surface is (Take g = 10 m−s2)a)0.2b)0.4c)0.6d)0.8Correct answer is option 'D'. Can you explain this answer?.
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