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On the horizontal surface of a truck, a block of mass 2 kg is placed and the coefficient of friction between the block and surface is (μs = 0.6) truck starts moving with an acceleration 4 m/s2 , the frictional force on the block will be? (g = 10 m/s2)
a)12N
b)10N
c)6N
d)8N
Correct answer is option 'D'. Can you explain this answer?
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Frictional force can be calculated using the equation:

Frictional force = coefficient of friction * Normal force

1. Finding the normal force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the block is placed on the horizontal surface of the truck. Since the truck is accelerating horizontally, there is an additional force acting on the block in the forward direction.

The weight of the block can be calculated using the equation:

Weight = mass * gravitational acceleration

Weight = 2 kg * 10 m/s^2 = 20 N

The normal force is equal in magnitude and opposite in direction to the weight of the block. Therefore, the normal force is also 20 N.

2. Finding the frictional force:
The frictional force can now be calculated using the equation mentioned earlier:

Frictional force = coefficient of friction * Normal force

Frictional force = 0.6 * 20 N = 12 N

Therefore, the frictional force on the block is 12 N.

The correct answer is option D) 12 N.
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On the horizontal surface of a truck, a block of mass 2 kg is placed a...
Option D is correct..
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On the horizontal surface of a truck, a block of mass 2 kg is placed and the coefficient of friction between the block and surface is (μs = 0.6) truck starts moving with an acceleration 4 m/s2 , the frictional force on the block will be? (g = 10 m/s2)a)12Nb)10Nc)6Nd)8NCorrect answer is option 'D'. Can you explain this answer?
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On the horizontal surface of a truck, a block of mass 2 kg is placed and the coefficient of friction between the block and surface is (μs = 0.6) truck starts moving with an acceleration 4 m/s2 , the frictional force on the block will be? (g = 10 m/s2)a)12Nb)10Nc)6Nd)8NCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about On the horizontal surface of a truck, a block of mass 2 kg is placed and the coefficient of friction between the block and surface is (μs = 0.6) truck starts moving with an acceleration 4 m/s2 , the frictional force on the block will be? (g = 10 m/s2)a)12Nb)10Nc)6Nd)8NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On the horizontal surface of a truck, a block of mass 2 kg is placed and the coefficient of friction between the block and surface is (μs = 0.6) truck starts moving with an acceleration 4 m/s2 , the frictional force on the block will be? (g = 10 m/s2)a)12Nb)10Nc)6Nd)8NCorrect answer is option 'D'. Can you explain this answer?.
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