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If car at rest acceleration uniformly to speed of 144km\h in 20 second, it covers a distance of?
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If car at rest acceleration uniformly to speed of 144km\h in 20 second...
Given Data
- Initial Speed (u) = 0 km/h (the car is at rest)
- Final Speed (v) = 144 km/h
- Time (t) = 20 seconds
Conversion of Speed
- To calculate distance, first convert speed from km/h to m/s.
- 144 km/h = (144 * 1000 m) / (3600 s) = 40 m/s
Finding Acceleration
- Acceleration (a) can be calculated using the formula:
a = (v - u) / t
- Substituting the values:
a = (40 m/s - 0 m/s) / 20 s = 2 m/s²
Calculating Distance Covered
- The distance (s) covered during acceleration can be calculated using the formula:
s = ut + 0.5at²
- Since u = 0, the equation simplifies to:
s = 0.5 * a * t²
- Substituting the values:
s = 0.5 * 2 m/s² * (20 s)²
s = 0.5 * 2 * 400 = 400 m
Final Result
- The car covers a distance of 400 meters while accelerating uniformly to a speed of 144 km/h over 20 seconds.
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If car at rest acceleration uniformly to speed of 144km\h in 20 second, it covers a distance of?
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