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Peter throws two different dice together and finds the product of the two numbers obtained. Rina throws a die and squares the number obtained who has the better chance to get the number 25?
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Peter throws two different dice together and finds the product of the ...
Comparison of Chances to Get 25
To determine who has a better chance of obtaining the number 25, we need to analyze the outcomes of both Peter’s and Rina’s throws.
Peter’s Outcomes
- Peter throws two different dice. The possible products of the two numbers can be calculated by multiplying the outcomes of each die.
- The maximum product from two dice (each ranging from 1 to 6) is 6 * 6 = 36, while the minimum is 1 * 1 = 1.
- To obtain the product of 25:
- The pairs that produce 25 are (5, 5) or (5, 5), but since the dice are different, this combination is not valid.
- Therefore, Peter cannot achieve a product of 25.
Rina’s Outcomes
- Rina throws a single die and squares the result. The possible outcomes are:
- 1^2 = 1
- 2^2 = 4
- 3^2 = 9
- 4^2 = 16
- 5^2 = 25
- 6^2 = 36
- Here, the only outcome that results in 25 is when she rolls a 5.
Probability Calculation
- Peter’s probability of getting 25 = 0 (as he cannot achieve this outcome).
- Rina’s probability of getting 25 = 1/6 (the chance of rolling a 5 on a single die).
Conclusion
- Rina has a better chance of obtaining the number 25, specifically a probability of 1/6, while Peter has no chance at all. Therefore, Rina clearly has the advantage in this scenario.
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Peter throws two different dice together and finds the product of the two numbers obtained. Rina throws a die and squares the number obtained who has the better chance to get the number 25?
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