UPSC Exam > UPSC Questions > What weight of calcium contains the same numb...
Start Learning for Free
What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur?
Most Upvoted Answer
What weight of calcium contains the same number of atoms as are presen...
Understanding the Problem
To find out how much calcium (Ca) contains the same number of atoms as in 3.2 g of sulfur (S), we need to follow a few steps involving molar mass and Avogadro's number.
Step 1: Calculate Moles of Sulfur
- Molar mass of sulfur (S) = 32 g/mol
- Moles of sulfur in 3.2 g = mass (g) / molar mass (g/mol)
- Moles of sulfur = 3.2 g / 32 g/mol = 0.1 mol
Step 2: Determine Number of Atoms in Sulfur
- Using Avogadro's number (6.022 x 10^23 atoms/mol):
- Number of atoms in 0.1 mol of sulfur = 0.1 mol x 6.022 x 10^23 atoms/mol = 6.022 x 10^22 atoms
Step 3: Calculate Required Moles of Calcium
- To find the same number of atoms in calcium, we also need 6.022 x 10^22 atoms.
- Therefore, moles of calcium required = number of atoms / Avogadro's number
- Moles of calcium = 6.022 x 10^22 atoms / 6.022 x 10^23 atoms/mol = 0.1 mol
Step 4: Calculate Mass of Calcium
- Molar mass of calcium (Ca) = 40 g/mol
- Mass of calcium = moles x molar mass
- Mass of calcium = 0.1 mol x 40 g/mol = 4 g
Conclusion
To have the same number of atoms as contained in 3.2 g of sulfur, you need 4 g of calcium.
To find out how much calcium (Ca) contains the same number of atoms as in 3.2 g of sulfur (S), we need to follow a few steps involving molar mass and Avogadro's number.
Step 1: Calculate Moles of Sulfur
- Molar mass of sulfur (S) = 32 g/mol
- Moles of sulfur in 3.2 g = mass (g) / molar mass (g/mol)
- Moles of sulfur = 3.2 g / 32 g/mol = 0.1 mol
Step 2: Determine Number of Atoms in Sulfur
- Using Avogadro's number (6.022 x 10^23 atoms/mol):
- Number of atoms in 0.1 mol of sulfur = 0.1 mol x 6.022 x 10^23 atoms/mol = 6.022 x 10^22 atoms
Step 3: Calculate Required Moles of Calcium
- To find the same number of atoms in calcium, we also need 6.022 x 10^22 atoms.
- Therefore, moles of calcium required = number of atoms / Avogadro's number
- Moles of calcium = 6.022 x 10^22 atoms / 6.022 x 10^23 atoms/mol = 0.1 mol
Step 4: Calculate Mass of Calcium
- Molar mass of calcium (Ca) = 40 g/mol
- Mass of calcium = moles x molar mass
- Mass of calcium = 0.1 mol x 40 g/mol = 4 g
Conclusion
To have the same number of atoms as contained in 3.2 g of sulfur, you need 4 g of calcium.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur?
Question Description
What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur?.
What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur?.
Solutions for What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? defined & explained in the simplest way possible. Besides giving the explanation of
What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur?, a detailed solution for What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? has been provided alongside types of What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? theory, EduRev gives you an
ample number of questions to practice What weight of calcium contains the same number of atoms as are present in 3.2 g of sulphur? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup