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A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0
sec the deer starts running and same moment, Cheetah slips from the branch and falls to
the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s
2 and
max speed of 30 m/s. The Deer has an acceleration of 4 m/s
2 and top speed of 24 m/s.
Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between
the deer and the tre?
sec the deer starts running and same moment, Cheetah slips from the branch and falls to
the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s
2 and
max speed of 30 m/s. The Deer has an acceleration of 4 m/s
2 and top speed of 24 m/s.
Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between
the deer and the tre?
Most Upvoted Answer
A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. ...
Scenario Overview
At time t = 0 sec, both the Cheetah and the Deer begin their respective motions. The Cheetah slips from a height of 5 m and starts chasing the Deer immediately after reaching the ground.
Cheetah's Parameters
- Initial Height: 5 m (falls to the ground)
- Acceleration: 10 m/s²
- Max Speed: 30 m/s
- Time to Catch Deer: 7 seconds
Deer's Parameters
- Acceleration: 4 m/s²
- Max Speed: 24 m/s
Cheetah's Fall Time
- The Cheetah falls from 5 m. The time to fall can be calculated using the formula:
t_fall = √(2h/g)
Here, g is approximately 10 m/s².
- t_fall ≈ √(2*5/10) = 1 sec.
Cheetah's Chase Dynamics
- After falling, the Cheetah takes 6 seconds (7 sec - 1 sec) to reach the Deer.
- In this time, the Cheetah accelerates up to the max speed of 30 m/s.
Distance Covered by Cheetah
- Using average speed (since it accelerates):
Average Speed = (0 + 30)/2 = 15 m/s
Distance = Speed x Time = 15 m/s x 6 sec = 90 m.
Distance Covered by Deer
- Deer accelerates for 7 seconds:
Distance = 0.5 * acceleration * time² = 0.5 * 4 * (7²) = 98 m.
Initial Distance Calculation
- The distance between the Deer and the tree when the Deer starts running:
Initial Distance = Distance covered by Deer - Distance covered by Cheetah
Initial Distance = 98 m - 90 m = 8 m.
Thus, the initial distance between the Deer and the tree was 8 meters.
At time t = 0 sec, both the Cheetah and the Deer begin their respective motions. The Cheetah slips from a height of 5 m and starts chasing the Deer immediately after reaching the ground.
Cheetah's Parameters
- Initial Height: 5 m (falls to the ground)
- Acceleration: 10 m/s²
- Max Speed: 30 m/s
- Time to Catch Deer: 7 seconds
Deer's Parameters
- Acceleration: 4 m/s²
- Max Speed: 24 m/s
Cheetah's Fall Time
- The Cheetah falls from 5 m. The time to fall can be calculated using the formula:
t_fall = √(2h/g)
Here, g is approximately 10 m/s².
- t_fall ≈ √(2*5/10) = 1 sec.
Cheetah's Chase Dynamics
- After falling, the Cheetah takes 6 seconds (7 sec - 1 sec) to reach the Deer.
- In this time, the Cheetah accelerates up to the max speed of 30 m/s.
Distance Covered by Cheetah
- Using average speed (since it accelerates):
Average Speed = (0 + 30)/2 = 15 m/s
Distance = Speed x Time = 15 m/s x 6 sec = 90 m.
Distance Covered by Deer
- Deer accelerates for 7 seconds:
Distance = 0.5 * acceleration * time² = 0.5 * 4 * (7²) = 98 m.
Initial Distance Calculation
- The distance between the Deer and the tree when the Deer starts running:
Initial Distance = Distance covered by Deer - Distance covered by Cheetah
Initial Distance = 98 m - 90 m = 8 m.
Thus, the initial distance between the Deer and the tree was 8 meters.
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A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre?
Question Description
A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre?.
A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre?.
Solutions for A Cheetah sitting on a tree branch 5 m above the ground, sees a deer. At t = 0 sec the deer starts running and same moment, Cheetah slips from the branch and falls to the ground. He immediatly starts chasing. Cheetah has an acceleration of 10 m/s 2 and max speed of 30 m/s. The Deer has an acceleration of 4 m/s 2 and top speed of 24 m/s. Cheetah was able to catch the deer at t = 7 secs. What is the initial distance between the deer and the tre? in English & in Hindi are available as part of our courses for UPSC.
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