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A unit mass at position vector r = 3 ICAP + 4 j cap is moving with velocity v is equals to 5 ICAP minus 6 j cap what is the angular momentum of the body about the origin?
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A unit mass at position vector r = 3 ICAP + 4 j cap is moving with vel...
To determine the angular momentum of a unit mass moving in a two-dimensional plane about the origin, we can follow a systematic approach.
Position Vector
- The position vector r of the mass is given as:
r = 3 i + 4 j
Velocity Vector
- The velocity vector v of the mass is:
v = 5 i - 6 j
Angular Momentum Formula
- The angular momentum L about the origin is calculated using the formula:
L = r × p
where p is the linear momentum, given by p = mv.
Since the mass m = 1, p = v.
Calculating Linear Momentum
- Therefore, the linear momentum p is:
p = 5 i - 6 j
Cross Product Calculation
- Now, we calculate the cross product of r and p:
L = r × p
= (3 i + 4 j) × (5 i - 6 j)
- Using the determinant method, we set up the matrix:
| i j k |
| 3 4 0 |
| 5 -6 0 |
- The determinant yields:
L = (0 - 0) i - (0 - 15) j + (-18 - 20) k
= 15 j - 38 k
Final Result
- Thus, the angular momentum L about the origin is:
L = 15 j - 38 k
This represents the angular momentum vector in terms of its components along the j and k axes.
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A unit mass at position vector r = 3 ICAP + 4 j cap is moving with velocity v is equals to 5 ICAP minus 6 j cap what is the angular momentum of the body about the origin?
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