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The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is
(a) 1.96ma
(b) 2.04mA
(c) 2mA
(d) 0.98mA?
(a) 1.96ma
(b) 2.04mA
(c) 2mA
(d) 0.98mA?
Most Upvoted Answer
The resulting change in the emitter current for change in the collecto...
Understanding Emitter and Collector Currents
When analyzing a transistor, particularly a BJT (Bipolar Junction Transistor), the relationship between emitter current (IE), collector current (IC), and the common base current gain (alpha) is crucial.
Key Relationships
- The collector current (IC) can be expressed as:
IC = alpha * IE
- The emitter current (IE) is related to collector current (IC) and base current (IB) as:
IE = IC + IB
From the relationship of these currents, we know:
- IE = IC / alpha
Given Data
- Change in collector current (ΔIC) = 2 mA
- Alpha (α) = 0.98
Calculating the Change in Emitter Current
1. Determine the Change in Base Current (IB):
- IB can be calculated using:
IB = IC * (1 - alpha) / alpha
However, since we need the change in emitter current for a change in collector current, we can simplify our approach:
2. Calculate the Change in Emitter Current (ΔIE):
- Using the formula:
ΔIE = ΔIC / alpha
- Substitute the values:
ΔIE = 2 mA / 0.98
3. Result:
- ΔIE = 2.04 mA (approximately)
Conclusion
Thus, the resulting change in the emitter current for a change in collector current of 2 mA, given alpha = 0.98, is approximately 2.04 mA. The correct answer is (b) 2.04 mA.
When analyzing a transistor, particularly a BJT (Bipolar Junction Transistor), the relationship between emitter current (IE), collector current (IC), and the common base current gain (alpha) is crucial.
Key Relationships
- The collector current (IC) can be expressed as:
IC = alpha * IE
- The emitter current (IE) is related to collector current (IC) and base current (IB) as:
IE = IC + IB
From the relationship of these currents, we know:
- IE = IC / alpha
Given Data
- Change in collector current (ΔIC) = 2 mA
- Alpha (α) = 0.98
Calculating the Change in Emitter Current
1. Determine the Change in Base Current (IB):
- IB can be calculated using:
IB = IC * (1 - alpha) / alpha
However, since we need the change in emitter current for a change in collector current, we can simplify our approach:
2. Calculate the Change in Emitter Current (ΔIE):
- Using the formula:
ΔIE = ΔIC / alpha
- Substitute the values:
ΔIE = 2 mA / 0.98
3. Result:
- ΔIE = 2.04 mA (approximately)
Conclusion
Thus, the resulting change in the emitter current for a change in collector current of 2 mA, given alpha = 0.98, is approximately 2.04 mA. The correct answer is (b) 2.04 mA.
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The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is(a) 1.96ma(b) 2.04mA(c) 2mA(d) 0.98mA?
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The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is(a) 1.96ma(b) 2.04mA(c) 2mA(d) 0.98mA? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is(a) 1.96ma(b) 2.04mA(c) 2mA(d) 0.98mA? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is(a) 1.96ma(b) 2.04mA(c) 2mA(d) 0.98mA?.
The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is(a) 1.96ma(b) 2.04mA(c) 2mA(d) 0.98mA? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is(a) 1.96ma(b) 2.04mA(c) 2mA(d) 0.98mA? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The resulting change in the emitter current for change in the collector of 2mA with alpha = 0.98 is(a) 1.96ma(b) 2.04mA(c) 2mA(d) 0.98mA?.
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