UPSC Exam > UPSC Questions > 13. The solution is prepared by mixing 25.0 g...
Start Learning for Free
13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water.
Determine the mole fractions of each component?
Determine the mole fractions of each component?
Most Upvoted Answer
13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 ...
Step 1: Calculate Moles of Each Component
To find the mole fractions, we first need to calculate the number of moles of ethanol and water.
- Molar Mass of Ethanol (C2H5OH): Approximately 46.07 g/mol
- Molar Mass of Water (H2O): Approximately 18.02 g/mol
- Moles of Ethanol:
- 25.0 g / 46.07 g/mol ≈ 0.543 moles
- Moles of Water:
- 25.0 g / 18.02 g/mol ≈ 1.387 moles
Step 2: Calculate Total Moles
- Total Moles:
- Moles of Ethanol + Moles of Water
- 0.543 moles + 1.387 moles ≈ 1.930 moles
Step 3: Calculate Mole Fractions
Mole fraction is calculated using the formula:
- Mole Fraction (X) = Moles of Component / Total Moles
- Mole Fraction of Ethanol (X_ethanol):
- 0.543 moles / 1.930 moles ≈ 0.281
- Mole Fraction of Water (X_water):
- 1.387 moles / 1.930 moles ≈ 0.719
Summary of Mole Fractions
- Mole Fraction of Ethanol:
- Approximately 0.281
- Mole Fraction of Water:
- Approximately 0.719
This calculation indicates that in the mixture, about 28.1% of the moles are ethanol, while 71.9% are water.
To find the mole fractions, we first need to calculate the number of moles of ethanol and water.
- Molar Mass of Ethanol (C2H5OH): Approximately 46.07 g/mol
- Molar Mass of Water (H2O): Approximately 18.02 g/mol
- Moles of Ethanol:
- 25.0 g / 46.07 g/mol ≈ 0.543 moles
- Moles of Water:
- 25.0 g / 18.02 g/mol ≈ 1.387 moles
Step 2: Calculate Total Moles
- Total Moles:
- Moles of Ethanol + Moles of Water
- 0.543 moles + 1.387 moles ≈ 1.930 moles
Step 3: Calculate Mole Fractions
Mole fraction is calculated using the formula:
- Mole Fraction (X) = Moles of Component / Total Moles
- Mole Fraction of Ethanol (X_ethanol):
- 0.543 moles / 1.930 moles ≈ 0.281
- Mole Fraction of Water (X_water):
- 1.387 moles / 1.930 moles ≈ 0.719
Summary of Mole Fractions
- Mole Fraction of Ethanol:
- Approximately 0.281
- Mole Fraction of Water:
- Approximately 0.719
This calculation indicates that in the mixture, about 28.1% of the moles are ethanol, while 71.9% are water.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component?
Question Description
13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component?.
13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component?.
Solutions for 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? defined & explained in the simplest way possible. Besides giving the explanation of
13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component?, a detailed solution for 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? has been provided alongside types of 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? theory, EduRev gives you an
ample number of questions to practice 13. The solution is prepared by mixing 25.0 grams of ethanol and 25.0 grams of water. Determine the mole fractions of each component? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup