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(A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?
(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2?
(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2?
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(A) A potential source is connected in parallel V by two wires of the ...
Equivalent Resistivity in Parallel Connection
When two resistive materials are connected in parallel, the equivalent resistance can be determined using the formula:
- 1/R_eq = 1/R1 + 1/R2
Where R1 and R2 are the resistances of the two materials.
- For materials with resistivities 1 (rho_1) and 2 (rho_2), the resistances can be expressed as:
- R1 = rho_1 * (L/A)
- R2 = rho_2 * (L/A)
Since both wires have the same length (L) and area (A), we can calculate the equivalent resistivity (rho_eq) as follows:
- R_eq = (rho_1 * rho_2) / (rho_1 + rho_2)
Substituting the values:
- R_eq = (1 * 2) / (1 + 2) = 2/3
Thus, the equivalent resistivity for the parallel connection is 2/3.
Equivalent Resistivity in Series Connection
In a series connection, the total resistance is simply the sum of the individual resistances:
- R_eq = R1 + R2
Using the same resistivities as before:
- R1 = rho_1 * (L/A)
- R2 = rho_2 * (L/A)
Therefore, the equivalent resistance can be expressed as:
- R_eq = (rho_1 + rho_2) * (L/A)
Substituting the values, we get:
- R_eq = (1 + 2) * (L/A) = 3 * (L/A)
The equivalent resistivity in this case will be simply:
- rho_eq = R_eq * (A/L) = 3
Thus, for the series connection, the equivalent resistivity is 3.
Conclusion
- For parallel connection: Equivalent resistivity = 2/3
- For series connection: Equivalent resistivity = 3
When two resistive materials are connected in parallel, the equivalent resistance can be determined using the formula:
- 1/R_eq = 1/R1 + 1/R2
Where R1 and R2 are the resistances of the two materials.
- For materials with resistivities 1 (rho_1) and 2 (rho_2), the resistances can be expressed as:
- R1 = rho_1 * (L/A)
- R2 = rho_2 * (L/A)
Since both wires have the same length (L) and area (A), we can calculate the equivalent resistivity (rho_eq) as follows:
- R_eq = (rho_1 * rho_2) / (rho_1 + rho_2)
Substituting the values:
- R_eq = (1 * 2) / (1 + 2) = 2/3
Thus, the equivalent resistivity for the parallel connection is 2/3.
Equivalent Resistivity in Series Connection
In a series connection, the total resistance is simply the sum of the individual resistances:
- R_eq = R1 + R2
Using the same resistivities as before:
- R1 = rho_1 * (L/A)
- R2 = rho_2 * (L/A)
Therefore, the equivalent resistance can be expressed as:
- R_eq = (rho_1 + rho_2) * (L/A)
Substituting the values, we get:
- R_eq = (1 + 2) * (L/A) = 3 * (L/A)
The equivalent resistivity in this case will be simply:
- rho_eq = R_eq * (A/L) = 3
Thus, for the series connection, the equivalent resistivity is 3.
Conclusion
- For parallel connection: Equivalent resistivity = 2/3
- For series connection: Equivalent resistivity = 3
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(A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2?
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(A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about (A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2?.
(A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about (A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2?.
Solutions for (A) A potential source is connected in parallel V by two wires of the same length and area made of materials with resistivities of 1 and 2, respectively. What would the equivalent resistivity be if the length and area were the same?(B) A source of potential V is connected in series with two wires that are of the same length and area but made of different resistivity materials (1 and 2). What would the equivalent resistivity be if the area were the same? 2? in English & in Hindi are available as part of our courses for Class 10.
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