The diagonal of a rectangle is 5 cm and one of at sides is 4 cm. Its area isa)20sq.cm.b)12 sq.cm.c)10 sq.cm.d)none of theseCorrect answer is option 'B'. Can you explain this answer?

Question

Accepted Answer

Given :-

one side = a = 4cm

nd diagonal = h = 5cm

Let, the other side be 'b'

Now,

By applying pythgoras theorem ;

find base,

b^2 = h^2 - p^2

b^2 = (5)^2 - (4)^2

b^2 = 25 - 16

b^2 = 9

b = 3

So, the two sides are 4cm and 3cm

Then ;

Area of rect. = length * breadth

ar. = 4 * 3

ar. = 12 cm^2

Answer

Given:
- Diagonal of a rectangle = 5 cm
- One side of rectangle = 4 cm

To find:
- Area of the rectangle

Solution:

Let's assume the other side of the rectangle be 'x'

Using Pythagoras theorem, we know that in a right-angled triangle, the square of the hypotenuse (Diagonal) is equal to the sum of squares of the other two sides.

Therefore, (4)^2 + (x)^2 = (5)^2
16 + x^2 = 25
x^2 = 25 - 16
x^2 = 9
x = √9
x = 3

So, the length and breadth of the rectangle are 3 cm and 4 cm respectively.

Now, we can calculate the area of the rectangle by multiplying length and breadth:
Area = length x breadth
Area = 3 cm x 4 cm
Area = 12 sq.cm

Hence, the correct answer is option B.

Answer

X=√5^2-4^2.
=√25-16
=√9
=3
area of a rectangle=3*4= 12

Answer

B

Answer

First make square of 5 nd 4 then answer will be 25 for 5 nd 16 for 4 so 25-16 will be 9 nd 9 is the square of 3 so multiply 3 by 4 to get answer 12

Answer

According to Pythagoras theorem  square the root 5 square and 2 square ,    then we get 25-16 = 9 root of this is 3 ,  so 3x4 = 12

Answer

B is the answer

Answer

25-16=9=3*4=12

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