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0.126 g of acid requires 20 ml of 0.1 N
NaOH for complete utilisation explain weight of the acid is?
NaOH for complete utilisation explain weight of the acid is?
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0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation...
Introduction
To determine the weight of the acid that reacts with NaOH, we need to analyze the reaction based on the given values.
Given Data
- Weight of acid = 0.126 g
- Volume of NaOH = 20 mL
- Normality of NaOH = 0.1 N
Moles of NaOH
- To calculate the moles of NaOH used, we use the formula:
Moles = Normality (N) × Volume (L)
- Converting mL to L:
20 mL = 0.020 L
- Thus, moles of NaOH = 0.1 N × 0.020 L = 0.002 moles
Acid-Base Neutralization
- In a typical acid-base reaction, the moles of acid will equal the moles of NaOH at the equivalence point.
- Therefore, the moles of the acid = 0.002 moles.
Molar Mass Calculation
- The molar mass of the acid can be calculated using the formula:
Molar Mass = Weight of Acid / Moles of Acid
- Plugging in the values:
Molar Mass = 0.126 g / 0.002 moles = 63 g/mol
Conclusion
- The weight of the acid utilized in this reaction is 0.126 g, with a calculated molar mass of 63 g/mol.
This analysis illustrates the stoichiometric relationship between the acid and NaOH, providing insights into their interaction during the neutralization process.
To determine the weight of the acid that reacts with NaOH, we need to analyze the reaction based on the given values.
Given Data
- Weight of acid = 0.126 g
- Volume of NaOH = 20 mL
- Normality of NaOH = 0.1 N
Moles of NaOH
- To calculate the moles of NaOH used, we use the formula:
Moles = Normality (N) × Volume (L)
- Converting mL to L:
20 mL = 0.020 L
- Thus, moles of NaOH = 0.1 N × 0.020 L = 0.002 moles
Acid-Base Neutralization
- In a typical acid-base reaction, the moles of acid will equal the moles of NaOH at the equivalence point.
- Therefore, the moles of the acid = 0.002 moles.
Molar Mass Calculation
- The molar mass of the acid can be calculated using the formula:
Molar Mass = Weight of Acid / Moles of Acid
- Plugging in the values:
Molar Mass = 0.126 g / 0.002 moles = 63 g/mol
Conclusion
- The weight of the acid utilized in this reaction is 0.126 g, with a calculated molar mass of 63 g/mol.
This analysis illustrates the stoichiometric relationship between the acid and NaOH, providing insights into their interaction during the neutralization process.
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0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation explain weight of the acid is?
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0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation explain weight of the acid is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation explain weight of the acid is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation explain weight of the acid is?.
0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation explain weight of the acid is? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation explain weight of the acid is? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.126 g of acid requires 20 ml of 0.1 N NaOH for complete utilisation explain weight of the acid is?.
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