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If the roots of the equation (a²+b²)x²-2(ac+bd)x+(c²+d²)=0 are equal,prove that a/b=c/d?
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If the roots of the equation (a²+b²)x²-2(ac+bd)x+(c²+d²)=0 are equal,p...
Understanding the Problem
The given quadratic equation is:
(a² + b²)x² - 2(ac + bd)x + (c² + d²) = 0.
We need to prove that if the roots are equal, then a/b = c/d.
Condition for Equal Roots
For a quadratic equation of the form Ax² + Bx + C = 0, the condition for equal roots is given by the discriminant being zero:
D = B² - 4AC = 0.
Here, we identify:
- A = a² + b²
- B = -2(ac + bd)
- C = c² + d²
Calculating the Discriminant
Now, we calculate the discriminant (D):
D = (-2(ac + bd))² - 4(a² + b²)(c² + d²)
Simplifying the discriminant:
D = 4(ac + bd)² - 4(a² + b²)(c² + d²)
Setting D = 0 gives us:
(ac + bd)² = (a² + b²)(c² + d²).
Applying Cauchy-Schwarz Inequality
From the equality condition of the Cauchy-Schwarz inequality:
(ac + bd)² ≤ (a² + b²)(c² + d²)
This implies that equality holds if and only if a/b = c/d.
Conclusion
Thus, we conclude that if the roots of the quadratic equation are equal, it necessarily leads to the relationship:
a/b = c/d.
This completes the proof.
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