The zeroes of the quadratic polynomial x2+ 99x + 127 area)both positiv...
Given quadratic polynomial is x2 + 99x + 127.
By comparing with the standard form, we get;
a = 1, b = 99 and c = 127
a > 0, b > 0 and c > 0
We know that in any quadratic polynomial, if all the coefficients have the same sign, then the zeroes of that polynomial will be negative.
Therefore, the zeroes of the given quadratic polynomial are negative.
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The zeroes of the quadratic polynomial x2+ 99x + 127 area)both positiv...
Understanding the Quadratic Polynomial
The given quadratic polynomial is x² + 99x + 127. To determine the nature of its roots (zeroes), we can use the properties of quadratic equations.
Roots of a Quadratic Equation
The roots of the polynomial can be found using the formula:
x = [-b ± √(b² - 4ac)] / 2a,
where a = 1, b = 99, and c = 127.
Discriminant Analysis
To analyze the nature of the roots, we look at the discriminant (D):
D = b² - 4ac = 99² - 4(1)(127).
Calculating the discriminant:
- 99² = 9801
- 4 * 1 * 127 = 508
- Therefore, D = 9801 - 508 = 9293.
Nature of the Roots
Now, let's evaluate the discriminant:
- Since D > 0, the quadratic has two distinct real roots.
Sum and Product of Roots
Using Vieta's formulas:
- The sum of the roots (α + β) = -b/a = -99.
- The product of the roots (αβ) = c/a = 127.
Evaluation of Roots
1. Sum of Roots:
- Since the sum is negative (-99), at least one of the roots must be negative.
2. Product of Roots:
- The product is positive (127), meaning both roots must be either positive or negative.
Since the sum is negative and the product is positive, it confirms that both roots must be negative.
Conclusion
Thus, the correct answer is option B: both negative.