500 bananas were divided equally among a certain number of students. I...
Consider x as number of bananas each student has with him/her and y as number of student.
Case 1: x*y=500 --- equation 1
If number of students increase by 25, y becomes (y+25).
And since each student will now receive 1 banana less, x becomes (x-1)
Therefore, Case 2: (x-1)*(y+25) --- equation 2
From equation 1, x=500/y
Using this in equation 2, we get
(500/y-1)(y+25)=500
Now solving the equation,
500+ 12500/y - y -25 = 500
12500/y = 25 + y
12500 = 25y + y^2
y^2 + 25y - 12500 = 0
Finding roots of the quadratic equation,
y^2 + 125y - 100y - 12500 = 0
y ( y+125 ) - 100 ( y+125 ) = 0
(y+125)*(y-100)=0
Therefore roots of y are y=100 and y=-125
Since only positive number is 100. So that is the answer which is 100 students.
500 bananas were divided equally among a certain number of students. I...
Given:
- Initially, there were 500 bananas.
- The bananas were divided equally among a certain number of students.
- If there were 25 more students, each would have received one banana less.
To find:
- The number of students.
Solution:
Let's assume the number of students initially is 'x'.
Dividing the 500 bananas equally among 'x' students means each student would receive 500/x bananas.
According to the given condition, if there were 25 more students, the number of students would be 'x + 25'. In this case, each student would receive one less banana, which means they would receive (500/x) - 1 bananas.
Since we are given that each student would receive one less banana, we can set up the following equation:
(500/x) - 1 = 500/(x + 25)
To solve this equation, we can cross multiply:
(x + 25) * (500/x) - 1 = 500
Expanding this equation, we get:
(500 * (x + 25))/x - 1 = 500
Now, let's simplify the equation:
(500x + 12500)/x - 1 = 500
Multiplying both sides of the equation by 'x' to eliminate the denominator, we have:
500x + 12500 - x = 500x
Simplifying further, we get:
12500 = x
Therefore, the number of students (x) is 12500.
Answer:
The correct option is (a) 100.