A transistor will operate in inverted region whena)Emitter junction is...
Forward-active (or simply active)
The base–emitter junction is forward biased and the base–collector junction is reverse biased. Most bipolar transistors are designed to afford the greatest common-emitter current gain, βF, in forward-active mode. If this is the case, the collector–emitter current is approximately proportional to the base current, but many times larger, for small base current variations
Reverse-active (or inverse-active or inverted)
By reversing the biasing conditions of the forward-active region, a bipolar transistor goes into reverse-active mode. In this mode, the emitter and collector regions switch roles. Because most BJTs are designed to maximize current gain in forward-active mode, the βF in inverted mode is several times smaller (2–3 times for the ordinary germanium transistor). This transistor mode is seldom used, usually being considered only for failsafe conditions and some types of bipolar logic. The reverse bias breakdown voltage to the base may be an order of magnitude lower in this region.
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A transistor will operate in inverted region whena)Emitter junction is...
**Answer:**
The operation of a transistor is determined by the biasing conditions applied to its junctions. The biasing conditions determine the region of operation of the transistor, which can be either active, cut-off, or saturation. In the case of an NPN transistor, the inverted region refers to the cut-off region.
To understand why option 'B' is the correct answer, let's examine each option and its corresponding biasing conditions:
a) Emitter junction is forward biased and collector junction is reverse biased:
- This biasing condition corresponds to the active region of operation, not the inverted region. In the active region, the transistor behaves as an amplifier.
b) Emitter junction is reverse biased and collector junction is forward biased:
- This biasing condition corresponds to the inverted region or the cut-off region. In this region, both the emitter-base junction and the collector-base junction are biased in such a way that no current flows through the transistor.
c) Emitter junction as well as collector junction are forward biased:
- This biasing condition corresponds to the saturation region of operation. In this region, the transistor acts as a switch and allows a maximum amount of current to flow through it.
d) Emitter junction as well as collector junction are reverse biased:
- This biasing condition corresponds to the active region of operation, not the inverted region. In the active region, the transistor behaves as an amplifier.
**In summary:**
- The correct answer is option 'B' because when the emitter-base junction is reverse biased and the collector-base junction is forward biased, the transistor operates in the inverted region or the cut-off region where no current flows through the transistor.
- The other options correspond to different regions of operation such as active or saturation regions.
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