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In a NPN transistor if the emitter junction is reverse biased and collector junction is reverse biased, the transistor will operate in
- a)active region
- b)saturation region
- c)cut-off region
- d)inverted region
Correct answer is option 'C'. Can you explain this answer?
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In a NPN transistor if the emitter junction is reverse biased and coll...
Explanation:
When a transistor is in reverse bias, it does not conduct current and acts as an open circuit. Therefore, if both the emitter and collector junctions of an NPN transistor are reverse biased, the transistor will not conduct and will be in cut-off region.
Cut-Off Region:
In the cut-off region, the transistor is in a state of non-conduction. There is no current flowing through the transistor, and the collector current is zero. The cut-off region is the region of a transistor's characteristic curve where the collector current is below a certain level and the transistor is said to be "cut off."
Inverted Region:
The inverted region is not a valid region of transistor operation. It is a region of operation in which the transistor operates as a negative resistance device. This region is not used in practical applications.
Active Region:
When the emitter-base junction of an NPN transistor is forward biased and the collector-base junction is reverse biased, the transistor operates in the active region. In this region, the transistor acts as an amplifier, and the collector current is proportional to the base current.
Saturation Region:
When the emitter-base junction of an NPN transistor is forward biased, and the collector-base junction is also forward biased, the transistor operates in the saturation region. In this region, the transistor acts as a switch, and the collector current is at its maximum value.
Conclusion:
In summary, if both the emitter and collector junctions of an NPN transistor are reverse biased, the transistor will operate in the cut-off region, and no current will flow through the transistor.
When a transistor is in reverse bias, it does not conduct current and acts as an open circuit. Therefore, if both the emitter and collector junctions of an NPN transistor are reverse biased, the transistor will not conduct and will be in cut-off region.
Cut-Off Region:
In the cut-off region, the transistor is in a state of non-conduction. There is no current flowing through the transistor, and the collector current is zero. The cut-off region is the region of a transistor's characteristic curve where the collector current is below a certain level and the transistor is said to be "cut off."
Inverted Region:
The inverted region is not a valid region of transistor operation. It is a region of operation in which the transistor operates as a negative resistance device. This region is not used in practical applications.
Active Region:
When the emitter-base junction of an NPN transistor is forward biased and the collector-base junction is reverse biased, the transistor operates in the active region. In this region, the transistor acts as an amplifier, and the collector current is proportional to the base current.
Saturation Region:
When the emitter-base junction of an NPN transistor is forward biased, and the collector-base junction is also forward biased, the transistor operates in the saturation region. In this region, the transistor acts as a switch, and the collector current is at its maximum value.
Conclusion:
In summary, if both the emitter and collector junctions of an NPN transistor are reverse biased, the transistor will operate in the cut-off region, and no current will flow through the transistor.
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In a NPN transistor if the emitter junction is reverse biased and coll...
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In a NPN transistor if the emitter junction is reverse biased and collector junction is reverse biased, the transistor will operate ina)active regionb)saturation regionc)cut-off regiond)inverted regionCorrect answer is option 'C'. Can you explain this answer?
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