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A power station has a maximum demand of 15000 KW. The annual load factor is 50% and plant capacity factor is 40%. What is the reserve capacity of the plant?
  • a)
    1875 KW
  • b)
    3750 KW
  • c)
    6000 KW
  • d)
    7500 KW
Correct answer is option 'B'. Can you explain this answer?
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A power station has a maximum demand of 15000 KW. The annual load fact...
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A power station has a maximum demand of 15000 KW. The annual load fact...
Given data:
Maximum demand (MD) = 15000 KW
Load factor (LF) = 50%
Plant capacity factor (PCF) = 40%

To find: Reserve capacity of the plant

Formula used:
Reserve capacity = MD - (MD * LF) / PCF

Calculation:
Substituting the given values in the formula, we get:
Reserve capacity = 15000 - (15000 * 0.5) / 0.4
Reserve capacity = 3750 KW

Therefore, the reserve capacity of the plant is 3750 KW.
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A power station has a maximum demand of 15000 KW. The annual load fact...
Utilisation factor = (max load ÷ plant capacity) = (15000÷40%) = 37500 capacity factor = (load factor*utilisation fator) = (50%*37500) = 18750 reserve capacity=(capacity factor - max demand) =(18750 - 15000) = 3750
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A power station has a maximum demand of 15000 KW. The annual load factor is 50% and plant capacity factor is 40%. What is the reserve capacity of the plant?a)1875 KWb)3750 KWc)6000 KWd)7500 KWCorrect answer is option 'B'. Can you explain this answer?
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