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AD is the altitude of an equilateral triangle ABC .On AD as base another equilateral triangle ADE is constructed .Prove that area( ∆ ADE) : area( ∆ ABC) = 3:4?
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AD is the altitude of an equilateral triangle ABC .On AD as base anoth...
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AD is the altitude of an equilateral triangle ABC .On AD as base another equilateral triangle ADE is constructed .Prove that area( ∆ ADE) : area( ∆ ABC) = 3:4?
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AD is the altitude of an equilateral triangle ABC .On AD as base another equilateral triangle ADE is constructed .Prove that area( ∆ ADE) : area( ∆ ABC) = 3:4? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about AD is the altitude of an equilateral triangle ABC .On AD as base another equilateral triangle ADE is constructed .Prove that area( ∆ ADE) : area( ∆ ABC) = 3:4? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for AD is the altitude of an equilateral triangle ABC .On AD as base another equilateral triangle ADE is constructed .Prove that area( ∆ ADE) : area( ∆ ABC) = 3:4?.
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