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In fig, O is the centre of the circle. PQ is tangent to the circle and secant PAB passes through the centre O. If PQ = 5 cm and PA = 1 cm, then the radius of the circle is
  • a)
    8 cm
  • b)
    12 cm
  • c)
    10 cm
  • d)
    6 cm
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In fig, O is the centre of the circle. PQ is tangent to the circle and...
AOB is the diameter of the circle since POB passes through O.
Now PA is the segment of the secant POB outside the circle.
So, by the tangent–secant rule, the square of the tangent = secant segment × segment of the secant outside the circle when a secant and tangent to a circle are drawn from a point outside the circle.
PB × PA = PQ × PA ⇒ PB = (PQ²) / PA
PB = (25²) / 1 = 625 / 1 = 25 cm
The diameter AOB = PB - PA = (25 - 1) cm = 24 cm
The radius = x = AOB / 2 = 24 cm / 2 = 12 cm
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In fig, O is the centre of the circle. PQ is tangent to the circle and secant PAB passes through the centre O. If PQ = 5 cm and PA = 1 cm, then the radius of the circle isa)8 cmb)12 cmc)10 cmd)6 cmCorrect answer is option 'B'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In fig, O is the centre of the circle. PQ is tangent to the circle and secant PAB passes through the centre O. If PQ = 5 cm and PA = 1 cm, then the radius of the circle isa)8 cmb)12 cmc)10 cmd)6 cmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In fig, O is the centre of the circle. PQ is tangent to the circle and secant PAB passes through the centre O. If PQ = 5 cm and PA = 1 cm, then the radius of the circle isa)8 cmb)12 cmc)10 cmd)6 cmCorrect answer is option 'B'. Can you explain this answer?.
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