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The height above surface of earth where the value of gravitational acceleration is one fourth of that at surface, will be
  • a)
     Re/4
  • b)
     Re/2
  • c)
    3Re/4
  • d)
    Re
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The height above surface of earth where the value of gravitational acc...
Understanding Gravitational Acceleration
Gravitational acceleration at the surface of the Earth (g) is approximately 9.81 m/s². As you move away from the Earth's surface, gravitational acceleration decreases according to the formula:
g' = g / (1 + h/R)²
Where:
- g' is the gravitational acceleration at height h,
- g is the gravitational acceleration at the surface (9.81 m/s²),
- R is the radius of the Earth (approximately 6400 km),
- h is the height above the surface.
Condition for One Fourth of Surface Gravity
To find the height where gravitational acceleration is one fourth of that at the surface, we set up the equation:
g' = g/4
Substituting the formula:
g / (1 + h/R)² = g/4
This simplifies to:
1 / (1 + h/R)² = 1/4
Taking the square root of both sides gives:
1/(1 + h/R) = 1/2
From this, we can derive:
1 + h/R = 2
This leads to:
h/R = 2 - 1
Thus,
h/R = 1
h = R
Conclusion: Height Above Earth's Surface
The height at which gravitational acceleration is one fourth of that at the Earth's surface is equal to the radius of the Earth (R). Therefore, the correct answer is:
Option D: Re
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Community Answer
The height above surface of earth where the value of gravitational acc...
To find the height above the Earth's surface where the gravitational acceleration is one-fourth of its value at the surface, we can use the formula for gravitational acceleration:
Thus, the height at which the gravitational acceleration is one-fourth of that at the Earth's surface is Re
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