Ya.. four gametes will form as:-
(TT), (tT), (Tt), (tt) !

in which three will tall ND one will dwarf !

Explanation:
Monohybrid cross is a genetic cross between two parents that differ in only one trait. In this type of cross, one allele from each parent is taken into consideration.

Let's take an example of a monohybrid cross between two plants with the genotype TT (homozygous dominant) and tt (homozygous recessive) for the trait of flower color.

During gamete formation, the alleles segregate independently of each other, and each gamete receives one allele from each parent. Therefore, the gametes produced by the Tt (heterozygous) F1 generation will be either T or t.

When the F1 generation is self-crossed, the Punnett square will look like this:

| | T | t |
|---|---|---|
| T | TT | Tt |
| t | Tt | tt |

From this, we can see that the F2 generation will have four possible genotype combinations: TT, Tt, Tt, and tt.

To calculate the types of gametes produced in the F2 generation, we use the formula 2^n, where n is the number of heterozygous gene pairs. In this case, there is only one heterozygous gene pair (Tt), so the formula becomes 2^1 = 2.

This means that there will be two types of gametes produced in the F2 generation: T and t. These gametes can combine in four different ways to form the four possible genotypes mentioned above.

Therefore, the correct answer is option B, which is 4.