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If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 cm .What is the nearest distance of distinct vision for him ?
- a)+298cm
- b)300cm
- c)-298cm
- d)-300cm
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 ...
∵ Near point = 75 cm and Power of lens = + 1 D
∴ P = 100 / f ( in cm )
f = 100 / P
= 100 / 1
= 100 cm
The distance of distinct vision v can be found as below.
Using lens formula here ,
1/f = 1/v - 1/u
⇒ 1/v = 1/f + 1/u
= 1 / 100 + 1 / - 75 = 3 - 4 / 300
= - 1 / 300
v = ₋300 cm
= - 3m ( in meters)
∴ P = 100 / f ( in cm )
f = 100 / P
= 100 / 1
= 100 cm
The distance of distinct vision v can be found as below.
Using lens formula here ,
1/f = 1/v - 1/u
⇒ 1/v = 1/f + 1/u
= 1 / 100 + 1 / - 75 = 3 - 4 / 300
= - 1 / 300
v = ₋300 cm
= - 3m ( in meters)
Most Upvoted Answer
If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 ...
Justification:
∵ Near point = 75 cm and Power of lens = + 1 D
∴ P = 100 / f ( in cm )
f = 100 / P
= 100 / 1
= 100 cm
The distance of distinct vision v can be found as below.
Using lens formula here ,
1/f = 1/v - 1/u
⇒ 1/v = 1/f + 1/u
= 1 / 100 + 1 / - 75 = 3 - 4 / 300
= - 1 / 300
v = ₋300 cm
= - 3m ( in meters)
∵ Near point = 75 cm and Power of lens = + 1 D
∴ P = 100 / f ( in cm )
f = 100 / P
= 100 / 1
= 100 cm
The distance of distinct vision v can be found as below.
Using lens formula here ,
1/f = 1/v - 1/u
⇒ 1/v = 1/f + 1/u
= 1 / 100 + 1 / - 75 = 3 - 4 / 300
= - 1 / 300
v = ₋300 cm
= - 3m ( in meters)
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Community Answer
If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 ...
Explanation:
To calculate the nearest distance of distinct vision for a person wearing spectacles, we need to consider the power of the spectacles.
The power of the spectacles is given as +1.0 Dioptre.
1. Understanding Dioptre:
- Dioptre is the unit used to measure the power of a lens.
- A positive Dioptre indicates that the lens is converging or convex.
- A negative Dioptre indicates that the lens is diverging or concave.
2. Relationship between Power and Focal Length:
- The power of a lens is inversely proportional to its focal length.
- The formula to calculate the focal length (f) in meters is: f = 1 / P
(where P is the power of the lens in Dioptres)
3. Calculation:
- Given that the power of the spectacles is +1.0 Dioptre.
- Using the formula, the focal length of the spectacles is: f = 1 / 1.0 = 1 meter.
- The nearest distance of distinct vision is the distance at which the eye can focus without any strain.
- For a normal eye, the nearest distance of distinct vision is considered to be 25 cm.
- However, when wearing spectacles, the focal length of the eye is effectively increased by the power of the spectacles.
- Therefore, the nearest distance of distinct vision for the person wearing spectacles with +1.0 Dioptre is: 1 meter + 25 cm = 1 meter + 0.25 meters = 1.25 meters.
- Converting 1.25 meters to centimeters, we get: 1.25 meters * 100 cm/meter = 125 cm.
So, the correct answer is option D) -300 cm, which is the nearest distance of distinct vision for a person wearing spectacles with +1.0 Dioptre.
To calculate the nearest distance of distinct vision for a person wearing spectacles, we need to consider the power of the spectacles.
The power of the spectacles is given as +1.0 Dioptre.
1. Understanding Dioptre:
- Dioptre is the unit used to measure the power of a lens.
- A positive Dioptre indicates that the lens is converging or convex.
- A negative Dioptre indicates that the lens is diverging or concave.
2. Relationship between Power and Focal Length:
- The power of a lens is inversely proportional to its focal length.
- The formula to calculate the focal length (f) in meters is: f = 1 / P
(where P is the power of the lens in Dioptres)
3. Calculation:
- Given that the power of the spectacles is +1.0 Dioptre.
- Using the formula, the focal length of the spectacles is: f = 1 / 1.0 = 1 meter.
- The nearest distance of distinct vision is the distance at which the eye can focus without any strain.
- For a normal eye, the nearest distance of distinct vision is considered to be 25 cm.
- However, when wearing spectacles, the focal length of the eye is effectively increased by the power of the spectacles.
- Therefore, the nearest distance of distinct vision for the person wearing spectacles with +1.0 Dioptre is: 1 meter + 25 cm = 1 meter + 0.25 meters = 1.25 meters.
- Converting 1.25 meters to centimeters, we get: 1.25 meters * 100 cm/meter = 125 cm.
So, the correct answer is option D) -300 cm, which is the nearest distance of distinct vision for a person wearing spectacles with +1.0 Dioptre.
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If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 cm .What is the nearest distance of distinct vision for him ?a)+298cmb)300cmc)-298cmd)-300cmCorrect answer is option 'D'. Can you explain this answer?
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