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If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 cm .What is the nearest distance of distinct vision for him ?

  • a)
    +298cm

  • b)
    300cm

  • c)
    -298cm

  • d)
    -300cm

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 ...
∵ Near point = 75 cm and Power of lens = + 1 D

∴    P = 100 / f ( in cm )

f = 100 / P

= 100 / 1

= 100 cm

The distance of distinct vision v can be found as below.

Using lens formula here ,

1/f  = 1/v - 1/u

⇒ 1/v = 1/f + 1/u

= 1 / 100 + 1 / - 75  =  3 - 4 / 300

= - 1 / 300

v = ₋300 cm

=  - 3m  ( in meters)
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Most Upvoted Answer
If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 ...
Justification:

∵ Near point = 75 cm and Power of lens = + 1 D

∴    P = 100 / f ( in cm )

f = 100 / P

= 100 / 1
= 100 cm

The distance of distinct vision v can be found as below.

Using lens formula here ,

1/f  = 1/v - 1/u

⇒ 1/v = 1/f + 1/u

= 1 / 100 + 1 / - 75  =  3 - 4 / 300

= - 1 / 300

v = ₋300 cm

=  - 3m  ( in meters)
Free Test
Community Answer
If the person uses spectacles of power + 1.0 Dioptre, Near point = 75 ...
Explanation:

To calculate the nearest distance of distinct vision for a person wearing spectacles, we need to consider the power of the spectacles.

The power of the spectacles is given as +1.0 Dioptre.

1. Understanding Dioptre:
- Dioptre is the unit used to measure the power of a lens.
- A positive Dioptre indicates that the lens is converging or convex.
- A negative Dioptre indicates that the lens is diverging or concave.

2. Relationship between Power and Focal Length:
- The power of a lens is inversely proportional to its focal length.
- The formula to calculate the focal length (f) in meters is: f = 1 / P
(where P is the power of the lens in Dioptres)

3. Calculation:
- Given that the power of the spectacles is +1.0 Dioptre.
- Using the formula, the focal length of the spectacles is: f = 1 / 1.0 = 1 meter.
- The nearest distance of distinct vision is the distance at which the eye can focus without any strain.
- For a normal eye, the nearest distance of distinct vision is considered to be 25 cm.
- However, when wearing spectacles, the focal length of the eye is effectively increased by the power of the spectacles.
- Therefore, the nearest distance of distinct vision for the person wearing spectacles with +1.0 Dioptre is: 1 meter + 25 cm = 1 meter + 0.25 meters = 1.25 meters.
- Converting 1.25 meters to centimeters, we get: 1.25 meters * 100 cm/meter = 125 cm.

So, the correct answer is option D) -300 cm, which is the nearest distance of distinct vision for a person wearing spectacles with +1.0 Dioptre.
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