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 If tan 2A = cot (A – 18°), then the value of A is
  • a)
    24°
  • b)
    18°
  • c)
    27°
  • d)
    36°
Correct answer is option 'D'. Can you explain this answer?
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If tan 2A = cot (A – 18°), then the value of A isa)24°...
 
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If tan 2A = cot (A – 18°), then the value of A isa)24°...
Tan2A=cot(A-18) cot(90-2A)= cot (A -18)90 -2A=A-18 90+18=A+2A 108=3A 3A=108° A=108/3 A=36°
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Community Answer
If tan 2A = cot (A – 18°), then the value of A isa)24°...
First of all..we should know that tan and cot are complementary angles...so tan B=cot (90-B) given tan 2A=cot (A-18) so cot(90-2A)=cot ( A-18) if cotA=cotB..and if A and B r acute angles then A=B so 90-2A=A-18 90+18=A+2A 3A=108 A=36 so value of A=36 degrees... hope u understand
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If tan 2A = cot (A – 18°), then the value of A isa)24°b)18°c)27°d)36°Correct answer is option 'D'. Can you explain this answer?
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