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You want find the sum of first 40 positive integer divisible by6?
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You want find the sum of first 40 positive integer divisible by6?
Positive integers divisible by 6 are 
6, 12, 18, 24,.... Since difference is same, it is an AP 
We need to find sum of first 40 integers 
We can use formula 
Sn = n/2 (2a + (n — 1) d) 
Here, n= 40, a = 6 
& d=12-6 =6 

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