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Water fall from a height 50m. If one third its mechanical energy converted into heat what will be the rise in temperature of water.
  • a)
    4°C
  • b)
    0.4°C
  • c)
    0.04°C
  • d)
    40°C
Correct answer is option 'C'. Can you explain this answer?
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Water fall from a height 50m. If one third its mechanical energy conve...
Introduction
When water falls from a height, it converts potential energy into kinetic energy. In this case, one third of the mechanical energy is converted into heat, resulting in an increase in the temperature of the water.
Step 1: Calculate Mechanical Energy
- The potential energy (PE) of the water at a height (h) can be calculated using the formula:
PE = mgh
where:
m = mass of water (in kg),
g = acceleration due to gravity (approximately 9.81 m/s²),
h = height (50 m).
Step 2: Energy Converted to Heat
- One third of the mechanical energy is converted to heat:
Heat Energy (Q) = (1/3) * PE.
Step 3: Calculate Temperature Rise
- The heat energy can be used to find the rise in temperature (ΔT) using the formula:
Q = mcΔT,
where:
c = specific heat capacity of water (approximately 4.18 J/g°C or 4180 J/kg°C).
- Rearranging gives:
ΔT = Q / (mc).
Step 4: Substitute Values
- Let's assume we have 1 kg of water for simplicity:
PE = 1 * 9.81 * 50 = 490.5 J.
Q = (1/3) * 490.5 J = 163.5 J.
- Now, using the specific heat capacity:
ΔT = 163.5 J / (1 kg * 4180 J/kg°C) ≈ 0.0391°C.
Conclusion
- The rise in temperature of the water is approximately 0.04°C, which matches option 'C'.
Thus, the answer is confirmed as option 'C'.
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