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Two candidates attempt to solve a quadratic equation of the form x2 + px + q = 0. One starts with a wrong
value of p and finds the roots to be 2 and 6. The other starts with a wrong value of q and finds the roots to be 2 and – 9. Find the correct roots of the equation :
  • a)
    3, 4
  • b)
    - 3, - 4
  • c)
    3, – 4
  • d)
    – 3, 4
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two candidates attempt to solve a quadratic equation of the form x2 + ...
If the roots are 2 and 6
then the quadratic equation will be
(x−2)(x−6)=0
⇒x2−6x−2x+12=0
⇒x2−8x+12=0
If the roots are 2 and −9then the quadratic equation will be
(x−2)(x+9)=0
⇒x2+9x−2x−18=0
⇒x2+7x−18=0
Now it is given that
p is wrong in the first quadratic equation and q is right and vice versa for the second quadratic equation
So, p=−8 is wrong and q=12 is right
Similarly p=7 is right and q=−18 is wrong
So taking the correct values of p and qour equation will become
x2+7x+12=0
⇒x2+4x+3x+12=0
⇒x=−3 and x=−4
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Most Upvoted Answer
Two candidates attempt to solve a quadratic equation of the form x2 + ...
• Only p is wrong => q is correct Roots are 2,6q = product of roots = 12• Only q is wrong => p is correctRoots are 2,-9p = sum of roots = -7If roots are a,b then ab = 12 and a + b = -7 ---(1)a - b = √((a + b)² - 4ab) = 1 ---(2)on adding (1) and (2) => 2a = -6 => a = -3=> b = a - 1 = -4Another way to do it is to factorise the equation having correct roots. Any quadratic equation is of the form,x² - (sum of roots)x + product of roots = 0=> x² + 7x + 12 = 0=> (x + 4)(x + 3) = 0=> x = -3, -4
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Community Answer
Two candidates attempt to solve a quadratic equation of the form x2 + ...
Let's denote the correct values of p and q as p* and q* respectively.

The first candidate starts with a wrong value of p and finds the roots to be 2 and 6. This means that the equation can be written as:

x^2 + px + q = (x - 2)(x - 6) = x^2 - 8x + 12

Comparing this with the original equation, we can see that:

p* = -8
q* = 12

The second candidate starts with a wrong value of q and finds the roots to be 2 and -6. This means that the equation can be written as:

x^2 + px + q = (x - 2)(x + 6) = x^2 + 4x - 12

Comparing this with the original equation, we can see that:

p* = 4
q* = -12

Therefore, the correct values of p and q are p* = -8 and q* = 12.
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Two candidates attempt to solve a quadratic equation of the form x2 + px + q = 0. One starts with a wrongvalue of p and finds the roots to be 2 and 6. The other starts with a wrong value of q and finds the roots tobe 2 and – 9. Find the correct roots of the equation :a)3, 4b)- 3, - 4c)3, – 4d)– 3, 4Correct answer is option 'B'. Can you explain this answer?
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