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A semicircle is drawn on AC. Two chords AB and BC of length 8 cm and 6 cm respectively are drawn in the semicircle. What is the measure of the diameter of the circle?
  • a)
    14 cm.
  • b)
    10 cm.
  • c)
    12 cm.
  • d)
    11 cm.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A semicircle is drawn on AC. Two chords AB and BC of length 8 cm and 6...
The diameter of circle is AC. Here ∠ABC is angle of semicircle. 

AB ∴ ∠ ABC = 90° ∴ Δ ABC is aright angled triangle. 

10 cm
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Most Upvoted Answer
A semicircle is drawn on AC. Two chords AB and BC of length 8 cm and 6...
Since the point B lies on the circumference of the semicircle. Therefore, angle B=90 Using Pythagoras theorem, AB^2+BC^2=AC^2 => 8^2 + 6^2=AC^2 => 64+36=AC^2 => AC^2=100 => AC=10cm
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Community Answer
A semicircle is drawn on AC. Two chords AB and BC of length 8 cm and 6...
The diameter of circle is AC. Here ∠ABC is angle of semicircle. 

AB ∴ ∠ ABC = 90° ∴ Δ ABC is aright angled triangle. 

10 cm
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A semicircle is drawn on AC. Two chords AB and BC of length 8 cm and 6 cm respectively are drawn in the semicircle. What is the measure of the diameter of the circle?a)14 cm.b)10 cm.c)12 cm.d)11 cm.Correct answer is option 'B'. Can you explain this answer?
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