Class 10 Exam > Class 10 Questions > What is the smallest number that when divided...
Start Learning for Free
What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case?
Verified Answer
What is the smallest number that when divided by 1723 and 29 becomes r...
The smallest number which when increased by 17 is exactly divisible by both 468 and 520 is obtained by subtracting 17 from the LCM of 468 and 520. Hence, the smallest number which when increased by 17 is exactly divisible by both 468 and 520 is 4663.
This question is part of UPSC exam. View all Class 10 courses
Most Upvoted Answer
What is the smallest number that when divided by 1723 and 29 becomes r...
Smallest number with remainders of 5
To find the smallest number that when divided by 1723 and 29 gives a remainder of 5 in each case, we need to consider the concept of the LCM (Least Common Multiple).
Finding the LCM of 1723 and 29
- First, find the prime factors of both numbers: 1723 = 1723 and 29 = 29
- To find the LCM, multiply the highest power of each prime factor together: LCM(1723, 29) = 1723 * 29
Calculating the number with remainders of 5
- To get a remainder of 5 when dividing by 1723 or 29, subtract 5 from the LCM: 1723 * 29 - 5
- Therefore, the smallest number that satisfies the condition is 49812 (1723 * 29 - 5 = 49812)
Therefore, the smallest number that when divided by 1723 and 29 gives a remainder of 5 in each case is 49812.
To find the smallest number that when divided by 1723 and 29 gives a remainder of 5 in each case, we need to consider the concept of the LCM (Least Common Multiple).
Finding the LCM of 1723 and 29
- First, find the prime factors of both numbers: 1723 = 1723 and 29 = 29
- To find the LCM, multiply the highest power of each prime factor together: LCM(1723, 29) = 1723 * 29
Calculating the number with remainders of 5
- To get a remainder of 5 when dividing by 1723 or 29, subtract 5 from the LCM: 1723 * 29 - 5
- Therefore, the smallest number that satisfies the condition is 49812 (1723 * 29 - 5 = 49812)
Therefore, the smallest number that when divided by 1723 and 29 gives a remainder of 5 in each case is 49812.
Attention Class 10 Students!
To make sure you are not studying endlessly, EduRev has designed Class 10 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 10.
|
|
Explore Courses for Class 10 exam
|
|
Similar Class 10 Doubts
Top Courses for Class 10View all
What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case?
Question Description
What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case?.
What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case?.
Solutions for What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? in English & in Hindi are available as part of our courses for Class 10.
Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Here you can find the meaning of What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? defined & explained in the simplest way possible. Besides giving the explanation of
What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case?, a detailed solution for What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? has been provided alongside types of What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? theory, EduRev gives you an
ample number of questions to practice What is the smallest number that when divided by 1723 and 29 becomes remainder of 5 in each case? tests, examples and also practice Class 10 tests.
|
|
Explore Courses for Class 10 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup