Two vessels A and B contain spirit and water in the ratio 5 : 2 and 7 ...
Spirit in 1 litre mix of A = 5/7 litre.
Spirit in 1 litre mix of B = 7/13 litre.
Spirit in 1 litre mix of C = 8/13 litre.
By rule of alligation we have required ratio X:Y
X : Y
5/7 7/13
\ /
(8/13)
/ \
(1/13) : (9/91)
7 9
Therefore required ratio = 1/13 : 9/91
= 7:9
View all questions of this test
Two vessels A and B contain spirit and water in the ratio 5 : 2 and 7 ...
Given information:
- Vessel A contains spirit and water in the ratio 5 : 2
- Vessel B contains spirit and water in the ratio 7 : 6
- Vessel C should contain spirit and water in the ratio 8 : 5
To find: Ratio in which A and B should be mixed to obtain the desired ratio in C
Solution:
Let's assume that A and B are mixed in the ratio x : y, where x represents the quantity of A and y represents the quantity of B.
From the given information, we can write the following equations:
- For vessel A: Spirit:Water = 5:2 => Spirit = (5/7)*(spirit+water), Water = (2/7)*(spirit+water)
- For vessel B: Spirit:Water = 7:6 => Spirit = (7/13)*(spirit+water), Water = (6/13)*(spirit+water)
- For vessel C: Spirit:Water = 8:5 => Spirit = (8/13)*(spirit+water), Water = (5/13)*(spirit+water)
Now, we can write the following equation based on the quantity of spirit in each vessel:
x*(5/7) + y*(7/13) = (x+y)*(8/13)
Solving this equation, we get:
x/y = 7/9
Therefore, A and B should be mixed in the ratio 7 : 9 to obtain the desired ratio in C.
Answer: Option D (7 : 9)
Two vessels A and B contain spirit and water in the ratio 5 : 2 and 7 ...
By alligation- 5/7 7/13 / 8/13 / 1/13 9/91 ie 7:9