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If p is a positive prime integer, then √p  is –
  • a)
    A rational number
  • b)
    An irrational number
  • c)
    A positive integer
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If p is a positive prime integer, then √p is –a)A rational...
Let us assume, to the contrary, that √p is
rational.
So, we can find coprime integers a and b(b ≠ 0)
such that √p = a/b
⇒ √p b = a
⇒ pb2 = a2 ….(i) [Squaring both the sides]
⇒ a2 is divisible by p
⇒  a is divisible by p
So, we can write a = pc for some integer c.
Therefore, a2 = p2c2 ….[Squaring both the sides]
⇒ pb2 = p2c2 ….[From (i)]
⇒ b2 = pc2
⇒ b2 is divisible by p
⇒ b is divisible by p
⇒ p divides both a and b.
⇒ a and b have at least p as a common factor.
But this contradicts the fact that a and b are coprime.
This contradiction arises because we have
assumed that √p is rational.
Therefore, √p is irrational.
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Community Answer
If p is a positive prime integer, then √p is –a)A rational...
Every integer between 1 and p-1 inclusive has an inverse modulo p. In other words, for any integer a between 1 and p-1, there exists an integer b between 1 and p-1 such that ab ≡ 1 (mod p). This is known as Fermat's Little Theorem.
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