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Aluminium reacts with caustic soda to form?
  • a)
    Sodium meta aluminate
  • b)
    Aluminium hydroxide
  • c)
    Aluminium oxide
  • d)
    Sodium tetra aluminate
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Aluminium reacts with caustic soda to form?a)Sodium meta aluminateb)Al...
Sodium aluminate is also formed by the action of sodium hydroxide on elemental aluminium which is an amphoteric metal. The reaction is highly exothermic once established and is accompanied by the rapid evolution of hydrogen gas. The reaction is sometimes written as: 2 Al + 2 NaOH + 2 H2O → 2 NaAlO2 + 3 H.
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Aluminium reacts with caustic soda to form?a)Sodium meta aluminateb)Al...
Formation of Sodium Meta Aluminate

When aluminium (Al) reacts with caustic soda (NaOH), sodium meta aluminate (NaAlO2) is formed along with the evolution of hydrogen gas (H2).

2Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2

Explanation

- Aluminium is a highly reactive metal and reacts with caustic soda, which is a strong base.
- Caustic soda (NaOH) dissociates in water to form sodium ions (Na+) and hydroxide ions (OH-).
- The hydroxide ions then react with the aluminium metal to form aluminium hydroxide (Al(OH)3).
- The aluminium hydroxide then reacts with more caustic soda to form sodium meta aluminate and water.
- The hydrogen gas is evolved as a byproduct of the reaction.

Uses of Sodium Meta Aluminate

Sodium meta aluminate is an important industrial chemical with many uses, including:

- It is used in the production of paper and pulp as a bleaching agent.
- It is used in the water treatment industry for the removal of impurities such as heavy metals and organic compounds.
- It is used as a catalyst in the production of biodiesel.
- It is used in the manufacturing of ceramics and glass.
- It is used in the textile industry as a scouring agent to remove impurities from fabrics.
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Aluminium reacts with caustic soda to form?a)Sodium meta aluminateb)Aluminium hydroxidec)Aluminium oxided)Sodium tetra aluminateCorrect answer is option 'A'. Can you explain this answer?
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