Let F(x) be a function such that F(x) F(x + 1) = – F(x – 1...
Solution:
Given, F(x) F(x 1) = F(x 1)F(x2)F(x3)F(x4) for all x 0.
We need to find the value of F(102).
Let's try to simplify the given equation by substituting x = 77, 78, 79...82.
F(77) F(78) = F(78) F(79) F(80) F(81)
F(78) F(79) = F(79) F(80) F(81) F(82)
F(79) F(80) = F(80) F(81) F(82) F(83)
Now, we can cancel the common terms from the above equations.
F(77) = F(82) F(81) F(80)
F(78) = F(83) F(82) F(81)
Substituting the given values of F(77) and F(83), we get:
9 = F(82) x 81 x F(80)
81 = F(83) x F(82) x 81
Dividing the above two equations, we get:
F(82) x F(80) = 9
Hence, we can write:
F(77) = 9 x F(81)
F(78) = 81 x F(81)
Again, substituting the given values of F(77) and F(83), we get:
9 x F(81) = F(82) x 81 x F(80)
F(82) x F(80) = 9
Therefore, we can write:
F(81) x F(82) x F(80) = 81
F(81) x 9 = 81
F(81) = 9
Now, substituting F(81) in the equation F(78) = 81 x F(81), we get:
F(78) = 729
Finally, substituting F(78) and F(81) in the equation F(77) = 9 x F(81), we get:
F(77) = 81
Hence, we can conclude that the given data is insufficient to find the value of F(102).
Let F(x) be a function such that F(x) F(x + 1) = – F(x – 1...
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