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In an examination, 80% students passed in philosophy and 70% students passed in maths. At the same time 15% failed in both the subjects. If390 students passed in both the subjects, how many students appeared in the examination?
- a)500
- b)400
- c)800
- d)600
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
In an examination, 80% students passed in philosophy and 70% students ...
15% failed in both the subjects ⇒ 85% passed in at least one of the subjects.
So, percentage of students passing both the subjects = 80 + 70 - 85 = 65%
So, 65% = 390 ⇒ 100% = 600
So, 65% = 390 ⇒ 100% = 600
Most Upvoted Answer
In an examination, 80% students passed in philosophy and 70% students ...
Here, 85% students are passed in any one of the subjects. Then According to set theory Students passed in both subjects=students passed in maths+students passed in philosophy -students passed in any one Students passed in both subjects = (80%+70%-85%)=65% Let total students be x Then x=(390×100)/65 =600
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In an examination, 80% students passed in philosophy and 70% students ...
Given information:
- 80% students passed in philosophy
- 70% students passed in maths
- 15% failed in both subjects
- 390 students passed in both subjects
To find:
- Total number of students appeared in the examination
Solution:
Let's assume the total number of students appeared in the examination as 'x'.
From the given information, we can say that:
- Number of students passed in philosophy = 80% of x
- Number of students passed in maths = 70% of x
- Number of students failed in both subjects = 15% of x
- Number of students passed in at least one subject = Total number of students passed in philosophy + Total number of students passed in maths - Number of students passed in both subjects
Using the above information, we can write the following equations:
Number of students passed in philosophy = 80% of x
Number of students passed in maths = 70% of x
Number of students failed in both subjects = 15% of x
Number of students passed in at least one subject = (80% of x) + (70% of x) - 390
We know that:
Number of students passed in at least one subject = Total number of students - Number of students failed in both subjects
Substituting the values, we get:
(80% of x) + (70% of x) - 390 = x - (15% of x)
or, 1.5x - 390 = 0.85x
or, 0.65x = 390
or, x = 600
Therefore, the total number of students appeared in the examination is 600.
Answer: Option D (600)
- 80% students passed in philosophy
- 70% students passed in maths
- 15% failed in both subjects
- 390 students passed in both subjects
To find:
- Total number of students appeared in the examination
Solution:
Let's assume the total number of students appeared in the examination as 'x'.
From the given information, we can say that:
- Number of students passed in philosophy = 80% of x
- Number of students passed in maths = 70% of x
- Number of students failed in both subjects = 15% of x
- Number of students passed in at least one subject = Total number of students passed in philosophy + Total number of students passed in maths - Number of students passed in both subjects
Using the above information, we can write the following equations:
Number of students passed in philosophy = 80% of x
Number of students passed in maths = 70% of x
Number of students failed in both subjects = 15% of x
Number of students passed in at least one subject = (80% of x) + (70% of x) - 390
We know that:
Number of students passed in at least one subject = Total number of students - Number of students failed in both subjects
Substituting the values, we get:
(80% of x) + (70% of x) - 390 = x - (15% of x)
or, 1.5x - 390 = 0.85x
or, 0.65x = 390
or, x = 600
Therefore, the total number of students appeared in the examination is 600.
Answer: Option D (600)
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In an examination, 80% students passed in philosophy and 70% students passed in maths. At the same time 15% failed in both the subjects. If390 students passed in both the subjects, how many students appeared in the examination?a)500b)400c)800d)600Correct answer is option 'D'. Can you explain this answer?
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