A cubical vessel of height 1m is full of water. Determine the minimum work done in taking out water from the vessel.




To find the minimum work done in taking out water from the vessel, we need to consider the potential energy of the water in the vessel.


- The vessel is cubical in shape.
- The height of the vessel is 1m.
- The vessel is full of water.


The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

In this case, the water in the vessel has a certain mass and is at a height of 1m. To take out the water, we need to bring it to ground level, which means the height will become zero. Therefore, the change in height (h) will be 1m.


Using the formula PE = mgh, we can calculate the potential energy of the water in the vessel.

PE = m * g * h

Since we are only interested in finding the minimum work done, we can assume that the mass of the water is 1kg (as the density of water is approximately 1000 kg/m^3).

PE = 1kg * 9.8 m/s^2 * 1m
PE = 9.8 J

Therefore, the minimum work done in taking out the water from the vessel is 9.8 Joules (J).


The minimum work done in taking out water from the vessel is 9.8 J.


The minimum work done in taking out water from a cubical vessel of height 1m is 9.8 Joules (J). This is calculated using the formula for potential energy, where the mass of the water is assumed to be 1kg.