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In 8085, usually the vector location and the next two memory location contain a JMP instruction. This allows the programs to branch to
- a)a longer subroutine
- b)a shorter subroutine
- c)a subroutine free path
- d)none of the above
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
In 8085, usually the vector location and the next two memory location ...
**Explanation:**
In the 8085 microprocessor, the vector location is the memory address where the processor jumps to when an interrupt is triggered. The vector location is usually stored in the first three memory locations after the interrupt is triggered.
The vector location points to a memory address that contains the starting address of the interrupt service routine (ISR). The ISR is a subroutine that handles the interrupt and performs the required tasks.
Typically, the next two memory locations after the vector location contain a JMP (jump) instruction. This JMP instruction is used to branch to a longer subroutine.
Here's why the correct answer is **option A** (a longer subroutine):
- When an interrupt occurs, the processor saves the current program counter (PC) on the stack and jumps to the vector location.
- The vector location points to the memory address where the JMP instruction is stored.
- The JMP instruction is used to branch to a longer subroutine, which is the actual ISR.
- The longer subroutine allows the microprocessor to perform more complex tasks in response to the interrupt.
- The JMP instruction allows the program flow to be redirected to the longer subroutine code.
- Once the ISR is completed, the program flow returns to the main program by popping the saved PC value from the stack and resuming execution from where it was interrupted.
Therefore, the presence of a JMP instruction in the vector location and the next two memory locations allows the programs to branch to a longer subroutine, which can handle more extensive tasks associated with the interrupt.
In the 8085 microprocessor, the vector location is the memory address where the processor jumps to when an interrupt is triggered. The vector location is usually stored in the first three memory locations after the interrupt is triggered.
The vector location points to a memory address that contains the starting address of the interrupt service routine (ISR). The ISR is a subroutine that handles the interrupt and performs the required tasks.
Typically, the next two memory locations after the vector location contain a JMP (jump) instruction. This JMP instruction is used to branch to a longer subroutine.
Here's why the correct answer is **option A** (a longer subroutine):
- When an interrupt occurs, the processor saves the current program counter (PC) on the stack and jumps to the vector location.
- The vector location points to the memory address where the JMP instruction is stored.
- The JMP instruction is used to branch to a longer subroutine, which is the actual ISR.
- The longer subroutine allows the microprocessor to perform more complex tasks in response to the interrupt.
- The JMP instruction allows the program flow to be redirected to the longer subroutine code.
- Once the ISR is completed, the program flow returns to the main program by popping the saved PC value from the stack and resuming execution from where it was interrupted.
Therefore, the presence of a JMP instruction in the vector location and the next two memory locations allows the programs to branch to a longer subroutine, which can handle more extensive tasks associated with the interrupt.
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In 8085, usually the vector location and the next two memory location contain a JMP instruction. This allows the programs to branch toa)a longer subroutineb)a shorter subroutinec)a subroutine free pathd)none of the aboveCorrect answer is option 'A'. Can you explain this answer?
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