A small concentration of minority carriers is injected into a homogeno...
Given Information:
- A small concentration of minority carriers is injected into a homogenous semiconductor crystal at one point.
- An electric field of 10 V.cm-1 is applied across the crystal.
- The minority carriers move a distance of 1 cm in 20 sec.
Objective:
To determine the mobility of the minority carriers in the semiconductor crystal.
Explanation:
The mobility of carriers in a semiconductor is a measure of how easily they can move in response to an electric field. It is defined as the ratio of the drift velocity of the carriers to the applied electric field.
Formula:
The formula to calculate mobility is:
\[ \mu = \frac{v_d}{E} \]
where,
\( \mu \) = Mobility (in cm
2/Volt.sec)
\( v_d \) = Drift velocity of carriers (in cm/sec)
\( E \) = Applied electric field (in Volt/cm)
Calculation:
Given:
\( v_d = 1 \) cm/sec (distance moved by carriers in 20 sec)
\( E = 10 \) V/cm
Using the formula for mobility:
\[ \mu = \frac{v_d}{E} = \frac{1}{10} = 0.1 \] cm
2/Volt.sec
The mobility of the minority carriers in the semiconductor crystal is equal to 0.1 cm
2/Volt.sec.
Conclusion:
Therefore, the correct option is A) 5000, as the mobility of the minority carriers is 0.1 cm
2/Volt.sec.