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Holes are injected into n-type Ge so that the at the surface of the semiconductor hole concentration is 1014/cm3. If diffusion constant of hole in Ge is 49cm2/sec and minority carrier life time is τp = 10-3 sec. Then the hole concentration Δp at a distance of 4mm from the surface is ______1014/cm3.
  • a)
    0.12
  • b)
    0.10
  • c)
    0.16
  • d)
    None of above
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Holes are injected into n-type Ge so that the at the surface of the se...

= 1.6 × 1013/cm3
= 0.16 × 1014/cm3
Free Test
Community Answer
Holes are injected into n-type Ge so that the at the surface of the se...
Given data:
- Hole concentration at the surface, p0 = 10^14 /cm^3
- Diffusion constant of hole, Dp = 49 cm^2/sec
- Minority carrier life time, τp = 10^-3 sec
- Distance from the surface, x = 4 mm = 0.4 cm

Formula:
The variation of hole concentration ∆p with distance x from the surface of the semiconductor is given by the equation:
∆p = p0 * exp(-x/√(Dp * τp))

Calculation:
Given p0 = 10^14 /cm^3, x = 0.4 cm, Dp = 49 cm^2/sec, τp = 10^-3 sec
Plugging these values into the formula:
∆p = 10^14 * exp(-0.4/√(49 * 10^-3))
∆p = 10^14 * exp(-0.4/√(0.049))
∆p = 10^14 * exp(-0.4/0.221)
∆p = 10^14 * exp(-1.809)
∆p = 0.16 * 10^14
∆p = 0.16 * 10^14 /cm^3
∆p = 0.16 * 10^14 /cm^3
∆p = 0.16 * 10^14 /cm^3
∆p = 0.16 * 10^14 /cm^3
∆p = 0.16 * 10^14 /cm^3
Therefore, the hole concentration at a distance of 4mm from the surface is 0.16 * 10^14 /cm^3 or 0.16 x 10^14 /cm^3. So, the correct answer is option 'C' - 0.16.
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Holes are injected into n-type Ge so that the at the surface of the semiconductor hole concentration is 1014/cm3. If diffusion constant of hole in Ge is 49cm2/sec and minority carrier life time is τp = 10-3 sec. Then the hole concentration Δp at a distance of 4mm from the surface is ______1014/cm3.a)0.12b)0.10c)0.16d)None of aboveCorrect answer is option 'C'. Can you explain this answer?
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Holes are injected into n-type Ge so that the at the surface of the semiconductor hole concentration is 1014/cm3. If diffusion constant of hole in Ge is 49cm2/sec and minority carrier life time is τp = 10-3 sec. Then the hole concentration Δp at a distance of 4mm from the surface is ______1014/cm3.a)0.12b)0.10c)0.16d)None of aboveCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Holes are injected into n-type Ge so that the at the surface of the semiconductor hole concentration is 1014/cm3. If diffusion constant of hole in Ge is 49cm2/sec and minority carrier life time is τp = 10-3 sec. Then the hole concentration Δp at a distance of 4mm from the surface is ______1014/cm3.a)0.12b)0.10c)0.16d)None of aboveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Holes are injected into n-type Ge so that the at the surface of the semiconductor hole concentration is 1014/cm3. If diffusion constant of hole in Ge is 49cm2/sec and minority carrier life time is τp = 10-3 sec. Then the hole concentration Δp at a distance of 4mm from the surface is ______1014/cm3.a)0.12b)0.10c)0.16d)None of aboveCorrect answer is option 'C'. Can you explain this answer?.
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