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Express sin67+cos75 in terms of trigonometric ratios of angles between 0 and 45?
Verified Answer
Express sin67+cos75 in terms of trigonometric ratios of angles between...
sin 67degree + cos 75degree

= cos 23degree + sin 15degree

This is according to the formula,

sin(90-∅) = cos∅ and
 
cos (90-∅) = sin Ф
This question is part of UPSC exam. View all Class 10 courses
Most Upvoted Answer
Express sin67+cos75 in terms of trigonometric ratios of angles between...
We know sin x =cos(90-x) cos x= sin(90-x) so sin 67+cos 75 =so cos 23+sin 15
Community Answer
Express sin67+cos75 in terms of trigonometric ratios of angles between...
Sin67=cos(90-67)=cos 23 cos75=sin(90-75)=sin15 so,sin67+cos75 can be expressed as cos23+sin15
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Express sin67+cos75 in terms of trigonometric ratios of angles between 0 and 45?
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Express sin67+cos75 in terms of trigonometric ratios of angles between 0 and 45? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Express sin67+cos75 in terms of trigonometric ratios of angles between 0 and 45? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Express sin67+cos75 in terms of trigonometric ratios of angles between 0 and 45?.
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