Class 10 Exam > Class 10 Questions > The sum of the areas of two squares is 468 m2...
Start Learning for Free
The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:
- a)18 m and 24 m
- b)6 m and 12 m
- c)12 m and 18 m
- d)24 m and 28 m
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The sum of the areas of two squares is 468 m2. If the difference of th...
Let sides of two squares be s1 nd s2...such that s1>s2.. now.. 4(s1-s2)=24m.. so.. (s1-s2)=6m... (1).. also.. s1^2+s2^2=468m^2... (s1-s2)^2+2s1s2=468... (6)^2+2s1s2=468...(using 1)... 2s1s2=432m^2..(2).. from(1), s1=s2+6.. on putting value of s1 in (2)... 2(s2+6)s2=432.. 2s2^2+12s2-432=0... s2^2+6s2-216=0.. s2^2+18s2-12s2-216=0.. s2(s2+18)-12(s2+18)=0.. (s2+18) (s2-12)=0.. so; s2=12m.. s2 can’t be 18m becoz Distance can't be negative. .. now, s1=(s2+6)=(12+6)m=18m...
Free Test
FREE
| Start Free Test |
Community Answer
The sum of the areas of two squares is 468 m2. If the difference of th...
Solution:
Let the sides of the two squares be a and b respectively.
Given, Sum of the areas of two squares = 468 m²
=> a² + b² = 468
Also, difference of their perimeters = 24 m
=> 4a - 4b = 24
=> a - b = 6
We can solve these equations simultaneously to find the values of a and b.
From the second equation, we get a = b + 6
Substituting this in the first equation, we get:
(b + 6)² + b² = 468
Simplifying this equation, we get:
2b² + 12b - 396 = 0
Dividing both sides by 2, we get:
b² + 6b - 198 = 0
Using the quadratic formula, we get:
b = (-6 ± √(6² + 4*198)) / 2
b = (-6 ± √(1800)) / 2
b = (-6 ± 30) / 2 (ignoring the negative root)
b = 12
Therefore, a = b + 6 = 18
Hence, the sides of the two squares are 12 m and 18 m.
Therefore, option (c) is correct.
Let the sides of the two squares be a and b respectively.
Given, Sum of the areas of two squares = 468 m²
=> a² + b² = 468
Also, difference of their perimeters = 24 m
=> 4a - 4b = 24
=> a - b = 6
We can solve these equations simultaneously to find the values of a and b.
From the second equation, we get a = b + 6
Substituting this in the first equation, we get:
(b + 6)² + b² = 468
Simplifying this equation, we get:
2b² + 12b - 396 = 0
Dividing both sides by 2, we get:
b² + 6b - 198 = 0
Using the quadratic formula, we get:
b = (-6 ± √(6² + 4*198)) / 2
b = (-6 ± √(1800)) / 2
b = (-6 ± 30) / 2 (ignoring the negative root)
b = 12
Therefore, a = b + 6 = 18
Hence, the sides of the two squares are 12 m and 18 m.
Therefore, option (c) is correct.
|
Explore Courses for Class 10 exam
|
|
Top Courses for Class 10View all
Question Description
The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer?.
The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 10.
Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Here you can find the meaning of The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, then the sides of the two squares are:a)18 m and 24 mb)6 m and 12 mc)12 m and 18 md)24 m and 28 mCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 10 tests.
|
|
Explore Courses for Class 10 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup