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A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed nikunj bro please help me
Most Upvoted Answer
A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach t...
Given:
Takeoff speed (v) = 88.3 m/s
Distance (d) = 1365 m

Acceleration:
We can use the formula, v^2 = u^2 + 2ad to find the acceleration (a) of the plane.
Here, initial velocity (u) = 0 m/s
v^2 = u^2 + 2ad
a = (v^2 - u^2)/2d
a = (88.3^2 - 0^2)/(2*1365)
a = 3.56 m/s^2

Therefore, the acceleration of the plane is 3.56 m/s^2.

Time Taken:
We can use the formula, v = u + at to find the time (t) taken by the plane to reach takeoff speed.
Here, initial velocity (u) = 0 m/s
v = u + at
t = (v-u)/a
t = (88.3 - 0)/3.56
t = 24.78 s

Therefore, the time taken by the plane to reach takeoff speed is 24.78 seconds.
Community Answer
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A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed nikunj bro please help me
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