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Aarti selects a card from a pack of well shuffled 52 playing cards. She needs an ace to win the game. The probability of Aarti losing the game is​
  • a)
    2/13
  • b)
    12/13
  • c)
    5/13
  • d)
    1/13
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Aarti selects a card from a pack of well shuffled 52 playing cards. Sh...
P(E) = number of expected trials / total number of trials
A standard deck of cards has 52 cards.
Number of expected trials = 4 x 12 = 48 cards
Total number of trials = 52
Therefore, P(E) = 48/52
= 12/13

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Most Upvoted Answer
Aarti selects a card from a pack of well shuffled 52 playing cards. Sh...
Total no. of aces in pack=4..
so,P[winning the game]=(4/52)=(1/13)..

i.e.P(losing the game)=1-P(winning the game)..

=1-(1/13)=12/13 .. (B).
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Community Answer
Aarti selects a card from a pack of well shuffled 52 playing cards. Sh...
P(E) = number of expected trials / total number of trials
A standard deck of cards has 52 cards.
Number of expected trials = 4 x 12 = 48 cards
Total number of trials = 52
Therefore, P(E) = 48/52
= 12/13
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Aarti selects a card from a pack of well shuffled 52 playing cards. She needs an ace to win the game. The probability of Aarti losing the game is​a)2/13b)12/13c)5/13d)1/13Correct answer is option 'B'. Can you explain this answer?
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