Mixture 1 contains 20% of water and mixture 2 contains 35% of water. 10 parts from 1st mixture and 4 parts from 2nd mixture is taken and put in a glass.What is the percentage of water in the new mixture of glass?a)17 (5/7)%b)24 (2/7)%c)28 (1/5)%d)24 (1/7)%e)18 (2/7)%Correct answer is option 'B'. Can you explain this answer?

Question

Answer

B) 24 (2/7)%
Explanation: Water in new mixture from 1st mixture = (20/100) * 10 = 2 parts Water in new mixture from 2nd mixture = (35/100) * 4 = 7/5 parts Required % =[ [2+ (7/5)]/(10+4)] * 100

Answer

To find the percentage of water in the new mixture of glass, we need to calculate the overall percentage of water in the combined mixture after taking 10 parts from the first mixture and 4 parts from the second mixture.

Let's assume that each part of the mixture is of equal quantity. Therefore, we can consider 10 parts as 10 units and 4 parts as 4 units.

Mixture 1:
- Contains 20% water
- Therefore, 10 units of mixture 1 will contain (20/100) * 10 = 2 units of water

Mixture 2:
- Contains 35% water
- Therefore, 4 units of mixture 2 will contain (35/100) * 4 = 1.4 units of water

Total water in the mixture:
- After combining 10 units from mixture 1 and 4 units from mixture 2, the total water in the mixture will be 2 + 1.4 = 3.4 units

Total mixture:
- After combining 10 units from mixture 1 and 4 units from mixture 2, the total mixture will be 10 + 4 = 14 units

Percentage of water in the new mixture:
- To find the percentage of water in the new mixture, we divide the total water (3.4 units) by the total mixture (14 units) and multiply by 100.
- Percentage of water in the new mixture = (3.4/14) * 100 ≈ 24.29%

Therefore, the correct answer is option B) 24 (2/7)%.

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