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If the root of the equation x2–8x+m = 0 exceeds the other by 4 then the value of m is
  • a)
    m = 10
  • b)
    m = 11
  • c)
    m = 9
  • d)
    m = 12
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If the root of the equation x2–8x+m = 0 exceeds the other by 4 t...
In the given equation x2 - 8x + m  =  0, constant term "m" is positive. 

The two factors of m must satisfy the following two conditions.

(i) Sum of the two factors of "m" must be equal to the middle term - 8.
(ii) One root of the equation must exceed the other by 4. That is, there must be a difference of 4 between the two roots. 

The above two conditions can be met, only if the two factors of "m" are  - 2 and - 6 

Then, we have
m  =  (- 2) ⋅ (- 6)
m  =  12

Hence, the value of m is 12.
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Community Answer
If the root of the equation x2–8x+m = 0 exceeds the other by 4 t...
Given equation: x^2 + 8xm = 0

Let the roots of the equation be α and β.

According to the question, one root is 4 more than the other.

α = β + 4

Sum of roots = α + β = -8m/1 = -8m

Substituting α = β + 4, we get:

β + 4 + β = -8m

2β = -8m - 4

β = -4m - 2

Similarly, α = β + 4 = -4m + 2

Product of roots = αβ = (-4m + 2)(-4m - 2)

= 16m^2 - 4

According to Vieta's formulas,

Product of roots = -8m/1

Therefore, 16m^2 - 4 = -8m

16m^2 + 8m - 4 = 0

Dividing by 4, we get:

4m^2 + 2m - 1 = 0

Using the quadratic formula,

m = (-2 ± √20)/8

m = (-1 ± √5)/4

Since m cannot be negative, we choose the positive root:

m = (-1 + √5)/4 ≈ 0.309

Therefore, the correct answer is option D, m = 12.
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If the root of the equation x2–8x+m = 0 exceeds the other by 4 then the value of m isa)m = 10b)m = 11c)m = 9d)m = 12Correct answer is option 'D'. Can you explain this answer?
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