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A, B, C, D and E are five taps. The capacity of B is 2 times that of A, the capacity of C is 3 times that of A. Capacities of D and E are 4 and 5 times that of A respectively. In the first case A, C and E act as input pipes and B and D act as output pipes.In the second case, C, D, E act as input pipes and A and B act as output pipes.If A and B working together as input pipes can fill the tank in 4 hours, then what is the difference in the time required to fill the tank in the first and second case stated above?

  • a)
    4/3 hours

  • b)
    3/3 hours

  • c)
    2/2 hours

  • d)
    1 hours

Correct answer is option 'A'. Can you explain this answer?
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A, B, C, D and E are five taps. The capacity of B is 2 times that of A...
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A, B, C, D and E are five taps. The capacity of B is 2 times that of A...
Given Information:
- Capacities of taps A, B, C, D and E are in the ratio of 1:2:3:4:5
- In the first case, A, C and E act as input pipes and B and D act as output pipes
- In the second case, C, D, E act as input pipes and A and B act as output pipes
- A and B working together can fill the tank in 4 hours

To Find: Difference in the time required to fill the tank in the first and second case

Solution:
1. Let's assume the capacity of A as x liters per hour.
2. Capacities of taps A, B, C, D and E are in the ratio of 1:2:3:4:5
- Capacity of A = x liters/hour
- Capacity of B = 2x liters/hour
- Capacity of C = 3x liters/hour
- Capacity of D = 4x liters/hour
- Capacity of E = 5x liters/hour
3. In the first case, A, C and E act as input pipes and B and D act as output pipes
- Total input capacity = x + 3x + 5x = 9x liters/hour
- Total output capacity = 2x + 4x = 6x liters/hour
- Net input capacity = 9x - 6x = 3x liters/hour
- Time taken to fill the tank = Total capacity / Net input capacity
- Let's assume the capacity of the tank is T liters
- Time taken to fill the tank in the first case = T / (3x) = T/3x hours
4. In the second case, C, D, E act as input pipes and A and B act as output pipes
- Total input capacity = 3x + 4x + 5x = 12x liters/hour
- Total output capacity = x + 2x = 3x liters/hour
- Net input capacity = 12x - 3x = 9x liters/hour
- Time taken to fill the tank = Total capacity / Net input capacity
- Time taken to fill the tank in the second case = T / (9x) = T/9x hours
5. A and B working together can fill the tank in 4 hours
- Capacity of A + Capacity of B = x + 2x = 3x liters/hour
- Time taken to fill the tank = Total capacity / (Capacity of A + Capacity of B)
- T / (3x) = 4
- T = 12x
6. Substituting the value of T in both cases
- Time taken to fill the tank in the first case = (12x) / (3x) = 4 hours
- Time taken to fill the tank in the second case = (12x) / (9x) = 4/3 hours
7. Difference in the time required to fill the tank in the first and second case
- 4 - 4/3 = 8/3 hours

Therefore, the difference in the time required to fill the tank in the first and second case is 8/3 hours.
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A, B, C, D and E are five taps. The capacity of B is 2 times that of A...
The correct Answer would be 8/3.
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A, B, C, D and E are five taps. The capacity of B is 2 times that of A, the capacity of C is 3 times that of A. Capacities of D and E are 4 and 5 times that of A respectively. In the first case A, C and E act as input pipes and B and D act as output pipes.In the second case, C, D, E act as input pipes and A and B act as output pipes.If A and B working together as input pipes can fill the tank in 4 hours, then what is the difference in the time required to fill the tank in the first and second case stated above?a)4/3 hoursb)3/3 hoursc)2/2 hoursd)1 hoursCorrect answer is option 'A'. Can you explain this answer?
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A, B, C, D and E are five taps. The capacity of B is 2 times that of A, the capacity of C is 3 times that of A. Capacities of D and E are 4 and 5 times that of A respectively. In the first case A, C and E act as input pipes and B and D act as output pipes.In the second case, C, D, E act as input pipes and A and B act as output pipes.If A and B working together as input pipes can fill the tank in 4 hours, then what is the difference in the time required to fill the tank in the first and second case stated above?a)4/3 hoursb)3/3 hoursc)2/2 hoursd)1 hoursCorrect answer is option 'A'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A, B, C, D and E are five taps. The capacity of B is 2 times that of A, the capacity of C is 3 times that of A. Capacities of D and E are 4 and 5 times that of A respectively. In the first case A, C and E act as input pipes and B and D act as output pipes.In the second case, C, D, E act as input pipes and A and B act as output pipes.If A and B working together as input pipes can fill the tank in 4 hours, then what is the difference in the time required to fill the tank in the first and second case stated above?a)4/3 hoursb)3/3 hoursc)2/2 hoursd)1 hoursCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A, B, C, D and E are five taps. The capacity of B is 2 times that of A, the capacity of C is 3 times that of A. Capacities of D and E are 4 and 5 times that of A respectively. In the first case A, C and E act as input pipes and B and D act as output pipes.In the second case, C, D, E act as input pipes and A and B act as output pipes.If A and B working together as input pipes can fill the tank in 4 hours, then what is the difference in the time required to fill the tank in the first and second case stated above?a)4/3 hoursb)3/3 hoursc)2/2 hoursd)1 hoursCorrect answer is option 'A'. Can you explain this answer?.
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