A man walks in straight 100 m and turns his right and walk 75 m. Again...
To solve this problem, we can break down Kewal's movements into a grid and calculate the distance from his starting point.
**Step-by-step solution:**
1. Start by drawing a grid. Assume Kewal's starting point is at the origin (0,0).
2. Kewal moves southeast a distance of 14m. This means he moves 14 units to the right (east) and 14 units down (south). So his new position is (14,-14).
3. Next, Kewal moves west a distance of 28m. Since he is moving west, his x-coordinate decreases by 28. So his new position is (-14,-14).
4. Kewal then moves northwest a distance of 14m. This means he moves 14 units to the left (west) and 14 units up (north). So his new position is (-28,0).
5. Finally, Kewal moves east a distance of 8m. Since he is moving east, his x-coordinate increases by 8. So his final position is (-20,0).
6. To find the distance between Kewal's final position and the origin (starting point), we can use the distance formula: distance = sqrt((x2-x1)^2 + (y2-y1)^2)
- Substitute the values into the formula: distance = sqrt((-20-0)^2 + (0-0)^2)
- Simplify: distance = sqrt((-20)^2 + 0^2)
- Calculate: distance = sqrt(400 + 0)
- Final answer: distance = sqrt(400) = 20
Therefore, Kewal is 20 meters away from his starting point. Hence, the correct answer is option A) 20m.
A man walks in straight 100 m and turns his right and walk 75 m. Again...