Class 10 Exam  >  Class 10 Questions  >  An object starting from rest moves on a strai... Start Learning for Free
An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ?
Most Upvoted Answer
An object starting from rest moves on a straight road for time t and c...
Explanation of the problem

Given, an object starting from rest moves on a straight road for time t and comes to rest finally. The distance is converted into two parts. In the first part, it is accelerated at constant acceleration X and then deaccelerated at rate Y.


Finding the maximum velocity

The maximum velocity can be found using the following steps:



  • Let the distance covered in the first part be d1 and the distance covered in the second part be d2.

  • Using the first equation of motion, we can find the velocity after the first part of the motion:


    • v = u + at

    • v = 0 + Xt

    • v = Xt


  • Using the third equation of motion, we can find the time taken to cover the first part of the motion:


    • s = ut + 1/2 at^2

    • d1 = 0 + 1/2 X t^2

    • t^2 = 2d1/X

    • t = sqrt(2d1/X)


  • Using the second equation of motion, we can find the final velocity after the second part of the motion:


    • v^2 = u^2 + 2as

    • v^2 = 0 + 2Yd2

    • v = sqrt(2Yd2)


  • Using the fourth equation of motion, we can find the time taken to cover the second part of the motion:


    • s = ut + 1/2 at^2

    • d2 = 0 + 1/2 Y t^2

    • t^2 = 2d2/Y

    • t = sqrt(2d2/Y)


  • The total time taken for the motion is:


    • total time = time taken in first part + time taken in second part

    • total time = sqrt(2d1/X) + sqrt(2d2/Y)


  • Therefore, the maximum velocity is:


    • maximum velocity = distance/time

    • maximum velocity = (d1 + d2)/(sqrt(2d1/X) + sqrt(2d2/Y))




Thus, the maximum velocity can be found using the above steps.
Community Answer
An object starting from rest moves on a straight road for time t and c...
One is the answer of your questions
Attention Class 10 Students!
To make sure you are not studying endlessly, EduRev has designed Class 10 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 10.
Explore Courses for Class 10 exam

Similar Class 10 Doubts

Top Courses for Class 10

An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ?
Question Description
An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ?.
Solutions for An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ? in English & in Hindi are available as part of our courses for Class 10. Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Here you can find the meaning of An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ? defined & explained in the simplest way possible. Besides giving the explanation of An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ?, a detailed solution for An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ? has been provided alongside types of An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ? theory, EduRev gives you an ample number of questions to practice An object starting from rest moves on a straight road for time t and comes to rest finally. The distant is converted in two parts. In first part it is accelerated at constant acceleration X and then deaccelerated at rate Y.Then what is the maximum vvelocit ? tests, examples and also practice Class 10 tests.
Explore Courses for Class 10 exam

Top Courses for Class 10

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev