Reaction of CH3-CH=CH2 with Acidified KMnO4

When a molecule of CH3-CH=CH2 is reacted with acidified KMnO4, a series of oxidation and reduction reactions occur. The overall reaction can be represented as follows:

CH3-CH=CH2 + 2KMnO4 + 3H2SO4 → 3MnSO4 + 2CO2 + 2H2O + K2SO4 + 3HSO4-

Step-by-Step Explanation

The reaction occurs in the following steps:

1. The acidified KMnO4 oxidizes the double bond of CH3-CH=CH2 to form a diol compound.

2. The diol compound is then further oxidized by the acidified KMnO4 to form a ketone.

3. The ketone is then oxidized to a carboxylic acid.

4. The MnO4- ions in the acidified KMnO4 are reduced to Mn2+ ions.

5. The H+ ions from the acidified KMnO4 react with the HSO4- ions present in the reaction mixture to form H2SO4.

6. The final products of the reaction are MnSO4, CO2, H2O, and K2SO4.

Conclusion

In conclusion, the reaction between CH3-CH=CH2 and acidified KMnO4 involves a series of oxidation and reduction reactions that ultimately result in the formation of MnSO4, CO2, H2O, and K2SO4. The double bond in the original molecule is oxidized to a diol, which is then further oxidized to a ketone and finally to a carboxylic acid. The MnO4- ions in the acidified KMnO4 are reduced to Mn2+ ions, and H+ ions react with HSO4- ions to form H2SO4.