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There are two particles of masses m and 2m placed at a distance‘d’ apart on a smooth horizontal surface. Where will the collision occur (with respect to original positions), if they are allowed to move towards each other because of their mutual attraction?
  • a)
    2d/3
  • b)
    d/2
  • c)
    2d
  • d)
    d
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
There are two particles of masses m and 2m placed at a distance‘...
Their collision will occur at their center of mass.
If we consider body of mass 'm' at origin & '2m' at distance "d" from 1st body on X-axis then, center of mass,
X = m1(x1)+m2(x2)/m1+m2
X = m(0)+2m(d)/m+2m
X = 2md/3m
X = 2d/3
Hence A is the correct answer.
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Community Answer
There are two particles of masses m and 2m placed at a distance‘...
Yes 'A' is correct
Their collision will occur at their center of mass
If we consider body of mass 'm' at origin & '2m' at distance "d" from 1st body on X-axis then,
center of mass,
x=m1(x1)+m2(x2)/m1+m2
 =m(0)+2m(d)/m+2m
 =2md/3m
 =2d/3
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There are two particles of masses m and 2m placed at a distance‘d’ apart on a smooth horizontal surface. Where will the collision occur (with respect to original positions), if they are allowed to move towards each other because of their mutual attraction?a)2d/3b)d/2c)2dd)dCorrect answer is option 'A'. Can you explain this answer?
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